Use "PEMDAS"
First we'll add then subtract
<span>tan θ is defined as the opposite/adjacent side to the angle in a triangle
in this case you have a triangle which forms from (0,0) to (5,0) and (5,15), with </span><span>θ at (0,0)
-> your x coordinate is the adjacent side, and y the opposite
</span>
<span>tan θ=opposite/adjacent=y/x=15/5=3</span>
Answer:
6.81m
Step-by-step explanation:
Using the formula for finding the length of am arc
L = theta/360° × 2πr
theta is the angle subtended by the drum in rotation
r is the radius of the drum
Given theta = 315.7°
r = 1.1m
Substituting the given values into the formula we have:
L = 315.7/360 × 2π(1.1)
L = 315.7/360 × 2.2π
L = 315.7/360 × 2.2(3.14)
L = 315.7/360 × 6.91
L = 6.81metres
Line of about 6.81metres will be wounded around the drum
Answer:
Step-by-step explanation:
There are an infinite number of possible solutions.
here's a few
(1 - 4i) + (-12 + 4i)
(-5.5 + 2i) + (-5.5 + i)
(-24 - 27i) + (13 + 30i)
f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
