Ask question

Ask question

All categories

2 years ago

13

Tayla purchased a large box of comic books for $300. She gave 15 of the comic books to her brother and then sold the rest on an

Internet website for $330, making a profit of $1.50 on each one. How many comic books were in the box

1 answer:

weeeeeb [17]2 years ago

3 0

Answer:

Number of comic books is 75.

Original price of each comic book is 4$.

Step-by-step explanation:

You might be interested in

1. A number plus 7 is at most 4.

nasty-shy [4]

Answer:

-3

4 - 7 = -3.

-3 + 7 = 4.

They are in a fact family.

The answer is -3.

Hope it helps!

3 0

2 years ago

Read 2 more answers

Find - 36<br> .<br> Ο +6<br> -6<br> 9Ο<br> Ο 18

Alinara [238K]

Answer:

+or-6

Step-by-step explanation:

This is a trick question. The answer would be the first choice since you're multiplying -6 by +or-6, meaning that it could still end up as a negative or a positive.

3 0

2 years ago

Read 2 more answers

Solve this multistep equation <br>12-5-16+3x=-23-9x

allsm [11]

The answer is x= -6/7<span><span></span></span>

3 0

3 years ago

For brainiest:):):):):):):):)

Nookie1986 [14]

Answer:

Step-by-step explanation:

original price = 20

3 0

3 years ago

Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.

Levart [38]

Answer:

The standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Step-by-step explanation:

We know that:

$4p\left(y-k\right)=\left(x-h\right)^2$ is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

$x^2\:+\:10x\:+\:6y\:=\:47$

Rewriting the equation in the standard form

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

where

vertex (h, k) = (-5, 12)

7 0

2 years ago