From a thin piece of cardboard 40 in by 40 in, square corners are cut out so that the sides can be folded up to make a box. what
dimensions will yield a box of maximum volume? what is the maximum volume?
1 answer:
The dimensions of the square base after cutting the corners will be (40-2x). The depth of the box will be x, so its volume is given by
V = x(40-2x)²
You can differentiate this to get
V' = 12x² -320x -1600
Setting this to zero and factoring gives
(3x-20)(x-20) = 0
The appropriate choice of solutions is
x = 20/3 = 6 2/3
The dimensions of the box of maximum volume are
26 2/3 in square by 6 2/3 in deep
The maximum volume is
(80/3 in)²(20/3 in) = 4740 20/27 in³
V = x(40-2x)²
You can differentiate this to get
V' = 12x² -320x -1600
Setting this to zero and factoring gives
(3x-20)(x-20) = 0
The appropriate choice of solutions is
x = 20/3 = 6 2/3
The dimensions of the box of maximum volume are
26 2/3 in square by 6 2/3 in deep
The maximum volume is
(80/3 in)²(20/3 in) = 4740 20/27 in³
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Answer:
Step-by-step explanation:
The base of the pyramid we need to study is a hexagon.
Let's look at the attached image of an hexagon to understand how we are going to find the area of this figure.
Notice that an hexagon is the combination of 6 exactly equal equilateral triangles in our case of size "2x" (notice that the "radius" of the hexagon is given as "2x")
Therefore the area of the hexagon is going to be 6 times the area of one of those equilateral triangles.
We know the area of a triangle is the product of its base times its height, divided by 2:
We notice that the triangle's height is exactly what is called the "apothem" of the hexagon (depicted in green in our figure) which measures , so replacing this value in the formula above for the area of one of the triangles:
Then we multiply this area times 6 to get the total area of the hexagon (6 of these triangles):
Area of hexagon =
which is the last option given in the list.
Answer:
Step-by-step explanation:
Subtract both sides from 35
Simplify:
Factor =0
Your answer will be z=57
and No solution