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mamaluj [8]
2 years ago
5

In a village, there was an epidemic and the population decreased by 10%. If there were only 1800 people left in the village, wha

t was the original population
of the village?
Mathematics
1 answer:
tester [92]2 years ago
7 0

\bold{\boxed{\huge{\blue{\underline{Answer }}}}}

\bold{\underline{ Given :- }}

\sf{The\: population\: is\: decreased \:by\: 10 percent  }

\sf{There\: were \: only \: 1800 \: people \: left}

\bold{\underline{ To\: Find :- }}

\sf{we \: have \: to \: find\: original \: population? }

\bold{\underline{ Let's \: Begin :- }}

\sf{Let \: the \: total \:  population\: be \: x }

\sf{\underline{ Therefore }}

\sf{According \: to \: the \: question }

\sf{ x - 10/100 = 1800 }

\sf{ 100x - 10/100 = 1800}

\sf{ 100x - 10 = 1800 × 100}

\sf{100x - 10 = 180000}

\sf{ 100x = 180000 + 10}

\sf{ x = 180010/100}

\sf{ x = 1800.1 }

\bold{\pink{Hence , The\: original \:population \:of \: the\: village \:is \:1800.1 }}

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4 0
2 years ago
Find the time required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, co
sineoko [7]

2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.

Step-by-step explanation:

The given is,

               Initial investment - $5000

               Future amount - $6000

               Interest rate - 7.5% (compounded quarterly)

Step:1

           Formula to calculate the Future amount with compound interest,

                                   F = P(1+\frac{r}{n} )^{nt}...................................(1)

          Where, F - Future amount

                           P - Initial amount

                            r - Rate of interest

                           n - No. of compounding in a year

                            t - Time period

          From given,

                      F = $6000

                      P = $5000

                       r = 7.5%

                       n = 4 (compounded quarterly)

        Equation (1) becomes,

                              6000=5000(1+\frac{0.075}{4} )^{(t)(4)}

                               \frac{6000}{5000} =(1+0.01875)^{4t}

                                 1.2 = (1.01875)^{4t}

         Take log on both sides,

                            log 1.2 = 4(t) log 1.01875

         Substitute log values,

                       0.07918 = 4(t) (0.0080676)

                                      = (t) (0.0322705)

                                   t = \frac{0.07918}{0.0322705}

                                      = 2.45

                                   t ≅ 2.5 years

Result:

         2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.

3 0
2 years ago
Please answer if true or false, thank you! links = report
lions [1.4K]

Answer:

see explanation

Step-by-step explanation:

a: false

b: true

c: true

d: true

hope this helps!

7 0
2 years ago
9 * 10^7 is how many times as large as 3 * 10^-2
WARRIOR [948]

Answer:

3,000,000 times larger

Step-by-step explanation:

9*10^7

= 9 multiplied by 10,000,000

=90,000,000

3*10^-2

= 3 multiplied by 0.01

= 0.03

Therefore by dividing 90,000,000 by 0.03

The answer is 3,000,000

That is 3 million

7 0
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larisa86 [58]

Step-by-step explanation:

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120-9π = 91.74 sq ft

7 0
2 years ago
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