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kaheart [24]
2 years ago
12

A car travels 274 km. It travels an average of 9.1 km on a litre of petrol. Write down a calculation you could do to find the nu

mber of litres used. please step by step explanation ​

Mathematics
2 answers:
Lilit [14]2 years ago
7 0

Answer:

30.1 litres

pls give me brainliest :)

Step-by-step explanation:

9.1km : 1 litre

274km: x

274=9.1x

274/9.1=9.1x/9.1

30.1 =x

liq [111]2 years ago
5 0

30.11 Litres Petrol

Step-by-step explanation:

Total distance= 274km

In 1 litre petrol is moves = 9.1km

Hence, The Total Petrol = 274/9.1= 30.11 km

I hope it'll help you...

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Write an equation for a like that is parallel to the given point. Explain how you found the equation.
pishuonlain [190]

Answer:

The line would be y = 2x + 5

Step-by-step explanation:

To find a parallel line, we first need to note that the slope of the original line is 2. This means the slope of our new line will also be 2 because parallel lines have the same slope.

So we use the slope we found along with the point given in point-slope form. Then we solve for y.

y - y1 = m(x - x1)

y - 11 = 2(x - 3)

y - 11 = 2x - 6

y = 2x + 5

7 0
3 years ago
What is the range of the function f(x) = 3x^2 + 6x - 8?
Airida [17]

R; all quadratic functions are going to have ranges and domains of *ALL REAL NUMBERS*.

3 0
3 years ago
-24 divided by x + 12 to the second when x= -14
ELEN [110]

Answer:12

Step-by-step explanation:

3 0
3 years ago
A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery servic
sineoko [7]

Answer:

55.32% probability that a late package was delivered by express delivery service 2

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Late delivery.

Event B: Service 2 was used.

A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery service 2.

100 - 35 = 65%.

So P(B) = 0.65

Service 2 has a record of 2.0% of packages being delivered late.

This means that P(A|B) = 0.02

Probability of a late delivery.

35% from service 1. Of those, 3% are late.

65% from service 2. Of those, 2% are late.

So

P(A) = 0.35*0.03 + 0.65*0.02 = 0.0235

What is the probability that a late package was delivered by express delivery service 2

P(B|A) = \frac{0.65*0.02}{0.0235} = 0.5532

55.32% probability that a late package was delivered by express delivery service 2

5 0
3 years ago
I just need like a step by step I haven't understood what my teacher has taught me here ​
motikmotik
You are trying to find the side between the right angle and the degree (This is known as the adjacent)
You are given degree 42
You also given the longest side of 19 (This is known as the hypothenuse)
Cosine: adjacent/hypothenuse
Cos42 = x/19
0.7431448255 = x/19
x = 19 * 0.7431448255
x = 14.11975168, round to tenth

Solution: x = 14.1
7 0
2 years ago
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