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2 years ago

Please answer this question thank you

Mathematics

2 answers:

Tanya [424]2 years ago

6 0

Answer:

Step-by-step explanation:

What I'm getting at, is that you need to add all the hour sold cups up, and then double it because she expects to sell twice as much. 15 + 11 +5 +6 = 37, and 37 doubled is 74

pashok25 [27]2 years ago

3 0

Answer:

74 cups

Step-by-step explanation:

Total for today: 37

6 + 5 + 11 + 15 = 37

Tomorrow is twice of today

2(37) = 74

I hope this helps!

You might be interested in

If the area of a square with side x is equal to the area of a triangle with base x, then find the altitude of the triangle.

zhannawk [14.2K]

Answer:

$h= 2x$

Step-by-step explanation:

Given

Square

$Side = x$

Triangle

$Base = x$

$Altitude = h$

Required

Find h, if both shapes have the same area

The area of the square is:

$Area = x * x$

$Area = x^2$

The area of the triangle is:

$Area = \frac{1}{2} * Base*Height$

$Area = \frac{1}{2} * x*h$

Equate both areas

$x^2 = \frac{1}{2} * x*h$

Divide both sides by x

$x = \frac{1}{2} *h$

Multiply both sides by 2

$2*x = \frac{1}{2} *h*2$

$2x = h$

$h= 2x$

3 0

2 years ago

Please can some explain how to identify angles that on the same segment?

sp2606 [1]

Step-by-step explanation:

Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.

Picture 1 a° = a° they are the same

Picture 2 p= 52° q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.

Picture 3 + 4 Let the obtuse angle MOQ = 2x.

Using the circle theorem, the angle at the centre is twice the angle at the circumference.

Therefore picture 4 tells us and proves;

Angle MNQ = x and angle MPQ = x.

Picture 5

A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.

The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.

Picture 6

The opposite angles in a cyclic quadrilateral add up to 180°.

a + c = 180°

b + d = 180°

Picture 7

Example

Calculate the angles a and b.

The opposite angles in a cyclic quadrilateral add up to 180°.

This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °

So hopefully this will help you remember the format here for quadrilateral shapes within a circle.

b = 180 - 140 = 40°

a = 180 - 60 = 120°