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alisha [4.7K]
2 years ago
9

un ingeniero realiza las siguientes observaciones sobre las ventas de inpresoras en una tienda hay impresoras epson hp y cannon

el nuero de impresoras epson y hp es cinco veces el numero de las cannon ademas el numero de impresoras epson es el triple ue el de la cannon y el total de imprsoras cannon y hp aciende a 123 resolver x el metodo gauss
Mathematics
2 answers:
puteri [66]2 years ago
7 0
What languages are you speaking
Likurg_2 [28]2 years ago
4 0
What language are you speaking
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Answer:

The answer is 640

Step-by-step explanation:

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2 years ago
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What is the area of rectangle ABCD, if points A, B, C, and D have the following coordinates?
slega [8]

Answer:

The area of the rectangle ABCD is \frac{2}{5} square units.

Step-by-step explanation:

From statement we have that rectangle ABCD is formed by the following points: A(x,y) = (2, 5), B(x,y) = \left(\frac{8}{3}, 5 \right), C(x,y) = \left(\frac{8}{3}, \frac{28}{5}  \right), D(x,y) = \left(2, \frac{28}{5} \right). First, we calculate the length of each side by the Pythagorean Theorem:

AB = \sqrt{\left(\frac{8}{3}-2 \right)^{2}+ (5-5)^{2}}

AB = \frac{2}{3}

BC = \sqrt{\left(\frac{8}{3}-\frac{8}{3}\right)^{2}+\left(\frac{28}{5}-5\right)^{2} }

BC = \frac{3}{5}

CD = \sqrt{\left(2-\frac{8}{3} \right)^{2}+\left(\frac{28}{5}-\frac{28}{5}  \right)^{2}}

CD = \frac{2}{3}

DA = \sqrt{\left(2-2\right)^{2}+\left(5-\frac{28}{5} \right)^{2}}

BC = \frac{3}{5}

Which satisfies all minimum characteristics for a rectangle. The area of the rectangle ABCD is the product of its base and its height, that is:

A = \left(\frac{2}{3}\right)\cdot \left(\frac{3}{5} \right)

A = \frac{2}{5}

The area of the rectangle ABCD is \frac{2}{5} square units.

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2 years ago
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3 years ago
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Answer:

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Step-by-step explanation:

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6 0
2 years ago
The age of Mary, Jo, and Larry have a sum of 120. Mary's age is three times Jo's age, and Larry's age is 5 less than Jo's age. F
rodikova [14]
Let  M = Mary's age.
Let J = Jo's age
Let L = Larry's age.

The sum of their ages is 120. Therefore
M + J + L = 120               (1)

Mary's age is three times Jo's age. Therefore
M = 3J                             (2)

Larry's age is 5 less than Jo's age. Therefore
L = J - 5                          (3)

Substitute (2) and (3) into (1).
3J + J + (J-5) = 120
3J + J + J - 5 = 120
5J - 5 = 120
5J = 120 + 5 = 125
J = 125/5 = 25

Therefore
J = 25,  M = 3J = 75,  L = J - 5 = 20
Answer:  Mary's age = 75;  Jo's age = 25;  Larry's age = 20

If Mary's age is 75, then Jo's age is 25, and Larry's age is 20.
5 0
3 years ago
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