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Sunny_sXe [5.5K]
3 years ago
11

I need help As Soon As possible!

Mathematics
1 answer:
Julli [10]3 years ago
6 0
This should be simple, add the Amounts of snow for the first week
4.32 + 6.86 = 11.18
-------------------------------------------------------
The subtract the amounts of snow from each week
11.18 - 7.89 = 3.29
---------------------------------------- 
C.) 3.29 is your answer
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What is the median of 90,30,20,30,60,30,80
MariettaO [177]

Answer:

you have an odd number, divide by 2 and round up to get the position of the median number.

Step-by-step explanation:

you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

4 0
3 years ago
Read 2 more answers
Mandy is saving money to buy a new car. For the past 5 weeks,she has $291 each week to her account . She also added $313 to her
arlik [135]

Answer: $2215

Step-by-step explanation:

For the past 5 weeks, Mandy adds $291 each week to her account. This gives $291×5= $1455

Money received on birthday= $313

Money started with in the account= $527

Total money in Mandy's account will be= $1455+$313+$527 = $2295

The total amount in Mandy's account is $2215

7 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!<br><br> Factor.<br><br> 64x^9 − 125y^6
shepuryov [24]

Identity:  \\ \boxed{  {a}^{3}   -  {b}^{3}  = (a - b)( {a}^{2}  + ab +   {b}^{2}) } \\  \\ 64 {x}^{9}  - 125 {y}^{6}  \\    \\ =  {(4 {x}^{3} )}^{3}  -  {(5 {y}^{2} )}^{3}  \\ \\   = (4 {x}^{3}  - 5 {y}^{2} )( \:  {(4 {x}^{3} )}^{2}  + 4 {x}^{3}  \times 5 {y}^{2}  +  {(5 {y}^{2} )}^{2}  \: ) \\  \\  = (4 {x}^{3}  - 5 {y}^{2} )(16 {x}^{6}  + 20 {x}^{3}  {y}^{2}  + 25 {y}^{4} )
7 0
3 years ago
Let a= x^2 +4. Rewrite the following equation in terms of a and set it equal to zero.
dusya [7]

Answer:


If:

a=x^{2}+4    (1)


And we have to rewrite the following expresion in terms of a:


{(x^{2}+4)}^{2}+32=12x^{2}+48   (2)


Firstly we have to rearrange the right side of equation (2) in terms of  x^{2}+4, factorizing by the common factor:


{(x^{2}+4)}^{2}+32=12(x^{2}+4)


Then, we can substitute x^{2}+4 by a:


a^{2}+32=12a


And set it equal to zero:

a^{2}-12a+32=0>>>>This is the resulting equation


Now, each term of an algebraic expresion (like the equation above) is composed of sign, coefficient, variable and exponent. The terms are separated from each other by the plus sign (+) or the minus sign (-).



In this case, the variable is a and the number that multiplies the variable (the coefficient) is -12, whereas the constant (which is the term with no variable) is 32





6 0
3 years ago
Read 2 more answers
Rocco can do 60 jumping jacks in 1 minute. How many jumping jacks can he do<br> in 8 minutes?
stich3 [128]

Answer:

480

Hope this helps

Step-by-step explanation:

6 0
3 years ago
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