Suzy bought a 20 ounce

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

2 years ago

Please help me I’m super confused on this problem!

Lorico [155]

Answer:

m < amc = 54°

Step-by-step explanation:

< amb and < bmc are complementary angles whose sum equals 90°.

Therefore, to find the value of 2x°, we must first solve for x.

We can establish the following equality statement:

< amb + < bmc = < amc

< 2x° + (x + 9)° = 90°

Combine like terms:

2x° + x° + 9° = 90°

3x° + 9° = 90°

Subtract 9 from both sides:

3x° + 9° - 9° = 90° - 9°

3x = 81°

Divide both sides by 3 to solve for x:

3x/3 = 81°/3

x = 27°.

Since x = 27°, substitute its value into 2x° to find m < amc:

2x° = 2(27°) = 54°

Therefore, m < amc = 54°

Please mark my answers as the Brainliest, if you find this helpful :)

5 0

2 years ago

Which of the following is the graph of y = cos(2x)?

irinina [24]

Answer:

Select the one which meets the following characteristics.

Step-by-step explanation:

y = cos(2x)

Characteristics:

Mean line at y = 0

Amplitude = 1

Period = 360/2 = 180° or pi radians

i.e one complete cos cycle is 0 to 180, next is 180 to 360 and so on

Range : from -1 to 1

5 0

2 years ago

Read 2 more answers

A book vendor is trying to sell his booking collection. One customer buys 1/4 of his books , another buys 1/3 of his books ,and

Anna11 [10]

Answer:

365535

Step-by-step explanation:

365535

7 0

2 years ago

Read 2 more answers

Evaluate the algebraic expressions, and put their values in order from least (1) to greatest (4), for a = 2 and b = 5 1. 50 − b2

Black_prince [1.1K]

Answer:

0

4

15

27

Step-by-step explanation:

a) The first expression is

$50-b^2+a$

When a=2 and b=5, we get

$50 - {(5)}^{2} + 2 = 50 - 25 + 2 = 27$

b) The second expression is

$a^2(5-b)$

We substitute a=2 and b=5;

${2}^{2} (5 - 5) = 4(5 - 5) = 4 \times 0 = 0$

c) The next expression is

${b}^{2} - 10$

We substitute b=5 to get:

${5}^{2} - 10 = 25 - 10 = 15$

d) The fourth expression is

$a(b-3)$

When a=2 and b=5

$2(5 - 3) = 2 \times 2 = 4$

We know that:

0<4<15<27

5 0

3 years ago