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3 years ago

Rewrite the fraction 29/50 with a denominator of 100

Mathematics

1 answer:

romanna [79]3 years ago

8 0

Answer:

58/100

50 X 2 = 100

29 X 2 = 58

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r-ruslan [8.4K]

Answer:

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Step-by-step explanation:

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2 years ago

A falcon flew 70 miles in 3 hours. What was the speed of the falcon?

adell [148]

Answer:

23.3333333 miles per hour

23 1/3 miles per hour

10.43093333333333 meters / second

Step-by-step explanation:

Take the distance and divide by the time to find the speed

70 miles / 3 hours

1 mile = 1609.34 meters

1 hours = 3600 seconds

70 miles /3 hours * 1 mile /1609.34 meters * 1 hours / 3600 seconds

10.43093333333333 meters / second

8 0

3 years ago

Read 2 more answers

4 divided by 457 is what

antiseptic1488 [7]

The answer to your question will be 114.25

4 0

3 years ago

Read 2 more answers

What Is a area with dimensions 1 unit times 1 unit

Ludmilka [50]

Area is length x width so if the dimensions are both 1,
the area is $1^{2}$

7 0

3 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

3 years ago