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Sholpan [36]
2 years ago
11

Find the 12th term of the geometric sequence 2, -8, 32, ...

Mathematics
2 answers:
Paha777 [63]2 years ago
5 0

The 12th term of the given geometric sequence is equal to -8,388,608.

<u>Given the following sequence:</u>

  • 2, -8, 32, ...

<h3>What is a geometric sequence?</h3>

A geometric sequence can be defined as a series of real and natural numbers that are generally calculated by multiplying the next number by the same number each time.

Mathematically, a geometric sequence is given by the expression:

a_n =a_1r^{n-1}

<u>Where:</u>

  • r is the common ratio.
  • a is the first term of a geometric sequence.

Substituting the given parameters into the formula, we have;

a_{12} =2 \times -4^{12-1}\\\\a_{12} =2 \times -4^{11}\\\\a_{12} =2 \times -4194304

12th term = -8,388,608.

Read more on geometric sequence here: brainly.com/question/12630565

lara31 [8.8K]2 years ago
3 0

Answer:

given that each term gets multiplied by -4 each time, you can then rewrite the geometric explicit formula ( a_n=a_1*r^(n-1) ) as a_12=2(-4)^(12-1). Next, you simplify the function, 2(-4)^11=2*-4194305=-8388608

Step-by-step explanation:

Hope this helps :3

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