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3 years ago

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Mathematics

1 answer:

Anton [14]3 years ago

8 0

8 cans

48/6=8

since each student collected equal amounts then divide the number of cans by the number of students

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Jack wants to share his candy with friends. Right now he has 4 1/3 pieces of chocolate. How many friends can he give 1/2 a candy

cricket20 [7]

Answer:

8 Friends

Step-by-step explanation:

First convert 4 1/3 to a mixed fraction

4 1/3 --> 13/3

Then divide by 1/2 to find how many friends per 1/2 candy bar with 13/3 candy bars

(13/3)/(1/2)

=(13*2)/(3*1)

=26/3

8.66667

Since you can't have 0.66667 of a person you get 8 friends to give candy to

3 0

3 years ago

What does the graph look like for y=-1/2 ×-2

Snezhnost [94]

My answer was deleted but ill post it again. it is a line plotted at the point (-2,-0.5) and the slope is down 1, right twice. this is a negative line.

6 0

3 years ago

A case of tomato cans weighs 563 dekagrams. A case of soup cans weighs 458 dekagrams. How much do the two cases weigh together i

oee [108]

Answer:

102,100 decigrams

Step-by-step explanation:

(564 dag + 458 dag) = 1021 dag

1021 dag × 100 dg/dag = 102100 dg

The two cases together weigh 102,100 decigrams.

_____

1 dag = 10 g

1 dg = 0.1 g

6 0

3 years ago

Read 2 more answers

PLS HELP ME, I REALLY NEED THIS RIGHT NOW, 100 POINTS, IF YOU ANSWER WITH NO EXPLANATION, OR ANSWER FOR THE POINTS YOU WILL BE R

Reika [66]

9514 1404 393

Answer:

0 ≤ m ≤ 7
0.4541 cm/month; average rate of growth over last 4 months of study

Step-by-step explanation:

Part A:

The study was concluded after 7 months. The fish cannot be expected to maintain exponential growth for any significant period beyond the observation period. A reasonable domain is ...

0 ≤ m ≤ 7

Part B:

The y-intercept is the value when m=0. It is the length of the fish at the start of the study.

Part C:

The average rate of change on the interval [3, 7] is given by ...

(f(7) -f(3))/(7 -3) = (4(1.08^7) -4(1.08^3))/4 = 1.08^3·(1.08^4 -1)

≈ 0.4541 cm/month

This is the average growth rate of the fish in cm per month over the period from 3 months to 7 months.

3 0

2 years ago

FIRST CORRECT ANSWER GETS BRAINLIEST AND 50 POINTS.

AnnyKZ [126]

Answer:

A) $5^3*5^{-4}=5^{3-4}=5^{-1}=\frac{1}{5}$ (Yes. It has a value between zero and one.)

B) $\frac{3^5}{3^{-6}}=3^{5-\left(-6\right)}=3^{5+6}=3^{11}=177147$ (No. It does not have a value between zero and one.)

C) $\left(\frac{1}{4}\right)^3* \left(\frac{1}{4}\right)^2=\left(\frac{1}{4}\right)^{3+2}=\left(\frac{1}{4}\right)^5=\frac{1^5}{4^5}=\frac{1}{1024}$ . (Yes. It has a value between zero and one.)

D) $\frac{\left(-7\right)^5}{\left(-7\right)^7}=\left(-7\right)^{5-7}=\left(-7\right)^{-2}=\frac{1}{\left(-7\right)^2}=\frac{1}{49}$ (Yes. It has a value between zero and one.)

4 0

4 years ago

Read 2 more answers