Answer:
int main()
{
double pH;
int neutral;
int base;
int acid;
cout<<"Enter a pH Value";
cin>> pH;
if(pH<7.0){
neutral =0;
base=0;
acid= 1;
}
else if (pH=7.0){
neutral =1;
base=0;
acid= 0;
}
else{
neutral =0;
base=1;
acid= 0;
}
cout <<"The neutral, Base and Acid Values are: "<<neutral<<","<<base<<","<<acid<<" Respectively"<<endl;
return 0;
}
Explanation:
Using multiple if/elseif/else statement the following problem is solved with C++
Answer:
ribbon- a row of tabs, groups, and commands
range- a group of cells containing related data
title bar- file name
cell- a container used to input data
worksheet- Excel’s version of a spreadsheet
Explanation:
Answer:
void doublelt(int *number)
{
*number=*number*2;
}
Explanation:
This exercise is for you to learn and understand the PASS BY POINTER syntax. The importance of this is that if you didnt use a pointer you would have to RETURN an int from the function. in that case the code would be:
int doublelt(int number)
{
number=number*2;
return number;
}
Passing by pointer manipulates the value by going inside the memory and where it resides. Without the pointer, the function would create COPIES of the argument you pass and delete them once the function ends. And you would have to use the RETURNED value only.
Answer:
hello your question is incomplete attached below is the complete question and answer
answer ; attached below
Explanation:
To prove this identity combination the right hand side has to be equal to the left hand side attached below is the prove showing that the right hand side is equal to the left hand side
