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stepladder [879]
3 years ago
9

1. A database table can hold ??

Computers and Technology
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

who are interested and I have been trying to

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dimaraw [331]

Answer:

Ok

Explanation:

4 0
2 years ago
What are the benefits of maintaining your vehicle?
Katarina [22]
<span>The correct answer is D - all of the above. It's important to maintain a vehicle to keep it road-worthy for as long as possible without compromising fuel economy, environmental impact or safety. It may also be a legal requirement.</span>
3 0
3 years ago
Read 2 more answers
HELLO!!!! For instance, will we get an error if we put a space after the word “print” and before the opening parenthesis in pyth
IceJOKER [234]

In python, spaces in the sense you're talking about, dont matter. For instance,

print ( "hello") will run the same as print("hello")

But, you cannot put a space before the print statement. That's called indenting. You are only supposed to indent code that is inside loops, if-elif-else statements, and functions.

7 0
2 years ago
5 of 10
DaniilM [7]

Answer:

what

Explanation:

3 0
2 years ago
An array is sorted (in ascending order) if each element of the array is less than or equal to the next element .
Aleks04 [339]

Answer:

// The program below checks if an array is sorted or not

// Program is written in C++ Programming Language.

// Comments are used for explanatory purpose

//Program Starts here

#include<iostream>

using namespace std;

//Function to check if the array is sorted starts here

int isSorted(int arr[], int count)

{

// Check if arrays has one or no elements

if (count == 1 || count == 0) {

return 1;

}

else

{

// Check first two elements

if(arr[0] >= arr[1])

{

return 0; // Not sorted

}

else

{ // Check other elements

int check = 0;

for(int I = 1; I<count; I++){

if (arr[I-1] > arr[I]) { // Equal number are allowed

check++; // Not sorted

}

}

}

if(check==0)

return isSorted(arr, count - 1); //Sorted

else

return 0; // Not sorted

}

// Main Method starts here

int main()

{

int count;

cin<<count;

int arr[count];

for(int I = 1; I<=count; I++)

{

cin>>arr[I-1];

}

int n = sizeof(arr) / sizeof(arr[0]);

if (isSorted(arr, n))

cout << "Array is sorted";

else

cout << "Array is not sorted";

}

8 0
3 years ago
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