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padilas [110]
2 years ago
12

3y - 2x = 9 slope intercept form

Mathematics
1 answer:
Alchen [17]2 years ago
5 0

Answer:

y=\frac{2}{3}x+3

Step-by-step explanation:

3y-2x=9\\\\3y=2x+9\\\\y=\frac{2}{3}x+3

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Dilate by a scale<br> factor of 1/2<br> AL<br> D
Firdavs [7]

Answer:

The image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:

  • D' (0, 1)
  • L' (1/2, 5/2) or L'(0.5, 2.5)
  • W' (5/2, 2) or W'(2.5, 2)

`The figure of the dilated image is attached below.

Step-by-step explanation:

Given the triangle ΔDLW withe the vertices

  • D(0, 2)
  • L(1, 5)
  • W(5, 4)

As the scale factor 1/2 < 0, thus the image triangle will be smaller than the original triangle.

The rule of dilation is given by

Dilation: (x, y)  →  (1/2x, 1/2y), centered at (0, 0)

D(0, 2)  → D' (1/2x, 1/2y) → D' (1/2(0), 1/2(2)) = D' (0, 1)

L(1, 5)  → L'(1/2x, 1/2y) →  L'(1/2(1), 1/2(5)) = L' (1/2, 5/2)

W(5, 4)  → W'(1/2x, 1/2y) →  W'(1/2(5), 1/2(4)) = W' (5/2, 2)

Therefore, the image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:

  • D' (0, 1)
  • L' (1/2, 5/2) or L'(0.5, 2.5)
  • W' (5/2, 2) or W'(2.5, 2)

`The figure of the dilated image is attached below.

7 0
3 years ago
Which coordinate point is a solution to the linear equation? (The graph counts by 1s)
Harman [31]

Answer:

the point through which it passes i.e (1,5)

5 0
2 years ago
Read 2 more answers
The scale of a map is 1:1,000,000. What are the real distances between two points if the distance between them on this map is: b
Dennis_Churaev [7]

Answer:

The real distance is 600,000\ cm  or 6\ km

Step-by-step explanation:

we know that

The scale of the map is 1:1,000,000

that means

1 cm in the map-------> represent 1,000,000 cm in the actual (real distance)

so

by proportion

\frac{1}{1,000,000}=\frac{0.6}{x}\\ \\x=0.6*1,000,000\\ \\x=600,000\ cm

Remember that

1\ km=100,000\ cm

so

600,000\ cm=6\ km

3 0
3 years ago
Give anther name for Plane WPX ​
SCORPION-xisa [38]
Answer:

Plane RXP

Explanation:

I’m pretty sure it’s right hope it helps
4 0
3 years ago
Given cscx/cotx=sqrt2, find a numerical value of one trigonometric function of x.
Firlakuza [10]

   \frac{csc (x)}{cot (x)} = \sqrt{2}

⇒ \frac{csc (x)}{1} * \frac{1}{cot (x)} = \sqrt{2}

⇒ \frac{1}{sin (x)} * \frac{sin(x)}{cos (x)} = \sqrt{2}

⇒\frac{1}{cos (x)} = \sqrt{2} ; sin(x) ≠ 0, cos(x) ≠ 0

⇒ \frac{cos (x)}{1} = \frac{1}{\sqrt{2}}; sin(x) ≠ 0, cos(x) ≠ 0

⇒ cos (x) = \frac{\sqrt{2}}{2}

Use the Unit Circle to determine when cos (x) = \frac{\sqrt{2}}{2}

Answer: 45° and 315°  (\frac{\pi}{4} and \frac{7\pi }{4} )


8 0
2 years ago
Read 2 more answers
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