Which of the following lists is in order from smallest to largest?

Mathematics

2 answers:

kakasveta [241]3 years ago

7 0

The order from smallest to largest is 1.1%, 0.1, 1/9, 2/11.

Step-by-step explanation:

To find the order of numbers from smallest to largest, first we have to convert the numbers in the same unit.

1/9 = 0.1111

0.1 = 0.1

1.1% = 0.011

2/11 = 0.1818

Now arrange the numbers from smallest to largest.

0.011 < 0.1 < 0.1111 < 0.1818

i.e. 1.1% < 0.1 < 0.011 < 0.1818

Therefore 1.1%, 0.1, 1/9, 2/11 is in the order from smallest to largest.

Bezzdna [24]3 years ago

5 0

Answer:

The order from smallest to largest is 1.1%, 0.1, 1/9, 2/11.

Step-by-step explanation:

To find the order of numbers from smallest to largest, first we have to convert the numbers in the same unit.

1/9 = 0.1111

0.1 = 0.1

1.1% = 0.011

2/11 = 0.1818

Now arrange the numbers from smallest to largest.

0.011 < 0.1 < 0.1111 < 0.1818

i.e. 1.1% < 0.1 < 0.011 < 0.1818

Therefore 1.1%, 0.1, 1/9, 2/11 is in the order from smallest to largest.

Step-by-step explanation:

You might be interested in

When proving the product, quotient, or power rule of logarithms, various properties of logarithms and exponents must be used.

Bingel [31]

When proving the properties of logarithms when exponents must be used, the property that is used in all of these is D. $log_{b} (b^y) = y$

<h3>What property is used in proving the properties of logarithms?</h3>

When proving any property of logarithms that have to do with exponents, one property that should always be used is $log_{b} (b^y) = y$ .

Expressing y as a product of $log_{b} (b^y)$ is the most basic property of using exponents on logs because it has both product, quotient, and power rules of logarithms.