Given the position function <em>s(t)</em>, you can get the acceleration function by differentiating <em>s</em> twice:
velocity = <em>s'(t)</em> = -5 sin(<em>t </em>) + 3 cos(3<em>t</em> )
acceleration = <em>s''(t)</em> = -5 cos(<em>t</em> ) - 9 sin(3<em>t</em> )
Then when <em>t</em> = <em>π</em>, the particle's acceleration is
<em>s''(π)</em> = -5 cos(<em>π</em>) - 9 sin(3<em>π</em>)
… = -5 • (-1) - 9 • 0 = 5
Answer:
6a+4b-14
Step-by-step explanation:
For this, we have to use the distributive property.
This means we multiply each value in the parentheses by 2.
2*3a=6a
2*2b=4b
2*(-7)=-14
So our equation is:
6a+4b-14
Answer:
Step-by-step explanation:
Let chocolate bar = c and blow pops = b
<u>As per given we have equations below:</u>
- 5c + 8b = 23.25
- 2c + 13b = 21.55
<u>13 times the first equation minus 8 times the second to eliminate b and find c:</u>
- 13(5c + 8b) - 8(2c + 13b) = 13(23.25) - 8(21.55)
- 65c - 16c = 129.85
- 49c = 129.85
- c = 129.85/49
- c = 2.65
Each chocolate bar costs $2.65
