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4 years ago

To increase an amount by 3% what single multiplier would you use?

1 answer:

3 0

3% is the decimal 0.03 .

To make a number 3% bigger, multiply it by 1.03 .

The ' 1 ' part is the amount that's already there, and
the ' .03 ' part is the amount to be added onto it.

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14 + 2(x – 3) = 4(x + 4)

strojnjashka [21]

Answer:

x= -4

Step-by-step explanation:

distribute

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subtract 4x from both sides

subtract 8 from both sides

divide both sides by -2

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3 years ago

Read 2 more answers

Information about the proportion of a sample that agrees with a certain statement is given below. Use StatKey or other technolog

Jet001 [13]

Answer:

The Attachment has the answer

Step-by-step explanation:

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4 years ago

PLEASE HELP! DUE VERY SOON

dedylja [7]

If I’m correct, it should be the first option, just to be sure, does n represent the number of years?

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3 years ago

Yoonie is a personnel manager in a large corporation. Each month she must review 16 of the employees. From past experience, she

Anarel [89]

Answer:

$P(3.25 < \bar X < 4.25)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\sigma_{\bar X}}$

And using the z score we have:

$P(\frac{3.5-4}{0.3}< Z< \frac{4.25-4}{0.3}) = P(-1.667< Z< 0.833)$

And we can use the normal standard distribution table or excel in order to find the probabilities and we got:

$P(-1.667< Z< 0.833)= P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the time it takes her to complete one review, and for this case we know the distribution for X is given by:

$X \sim N(4,1.2)$

Where $\mu=4$ and $\sigma=1.2$

And we select a sample size of n =16. Since the dsitribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by: