Answer:
Tap A 3hrs
Tap B 6hrs
Step-by-step explanation:
Let the volume of the swimming pool be Xm^3.
Now, to get the appropriate volume, we know we need to multiply the rate by the time. Let the rate of the taps be R1 and R2 respectively, while the time taken to fill the swimming pool be Ta and Tb respectively.
x/Ta= Ra
x/Tb= Rb
X/(Ra + Rb)= 2
Ta = Tb - 3
From equation 2:
X = 2( Ra + Rb)
Substituting the values of Ra and Rb Using the first set of equations
X = 2( x/Ta + x/Tb)
But Ta = Tb - 3
1/2 = 1/(Tb - 3)+ 1/Tb
0.5 = (Tb + Tb-3)/Tb(Tb - 3)
At this juncture let’s say Tb = y
0.5 = (2y - 3)/y(y - 3)
y(y-3 ) = 4y - 6
y^2 -3y - 4y + 6 = 0
y^2 -7y + 6= 0
Solving the quadratic equation, we get y =
y = Tb = 6hrs or 1hr
We remove one hour as we know that Tap A takes 3hrs left than tap B and there is nothing like negative hours
Now, we get Ta by Tb -3 = 6 - 3 = 3hrs
Answer:
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Step-by-step explanation:
That should help
Answer:
x = 10
Step-by-step explanation:
2x/3 + 1 = 7x/15 + 3
<em><u>(times everything in the equation by 3 to get rid of the first fraction)</u></em>
2x + 3 = 21x/15 + 9
<em><u>(times everything in the equation by 15 to get rid of the second fraction)</u></em>
30x+ 45 = 21x + 135
<em><u>(subtract 21x from 30x; subtract 45 from 135)</u></em>
9x = 90
<em><u>(divide 90 by 9)</u></em>
x = 10
<h2>
Another solution:</h2>
2x/3 + 1 = 7x/15 + 3
<u><em>(find the LCM of 3 and 15 = 15)</em></u>
<u><em>(multiply everything in the equation by 15, then simplify)</em></u>
10x + 15 = 7x + 45
<u><em>(subtract 7x from 10x; subtract 15 from 45)</em></u>
3x = 30
<em><u>(divide 30 by 3)</u></em>
x = 10
Your answer would be 33 lb. hope that helped
Answer:
h(-2)=-6
g(2)=-7
Step-by-step explanation:
Just plug 2 in for x and solve the equation.
