Answer:
65.75 deg
Explanation:
v = initial speed of launch of projectile
θ = initial angle of launch
H = maximum height of the projectile
maximum height of the projectile is given as
eq-1
D = horizontal range of the projectile
horizontal range of the projectile is given as
eq-2
It is also given that
D = 1.8 H
using eq-1 and eq-2
tanθ = 2.22
θ = 65.75 deg
Answer:
is a reflection.
The image is real light rays actually focus at the image location). As the object moves towards the mirror the image location moves further away from the mirror and the image size grows (but the image is still inverted). When the object is that the focal point, the image is at infinity.
Explanation:
Answer:
Explanation:
= Charge at 3000 m = 40 C
= Charge at 1000 m = -40 C
= 3000 m
= 1000 m
k = Coulomb constant =
Electric field due to the charge at 3000 m
Electric field due to the charge at 1000 m
Electric field at the aircraft is .
Answer:
Explanation:
The dart will go forward horizontally with velocity of 19 m/s. It will also fall downwards with initial velocity of zero and gravitational acceleration of 9.8 m/s².
Distance PQ covered by the dart can be calculated using the following formula.
s = ut + 1/2 at²
u is initial velocity , a is acceleration and t is time.
Putting the values
s = 0 + 1/2 x 9.8 x .19²
= .1769 m
= 17.69 cm.
Explanation:
there are 4 phases in which matter could be classified.
1. Solid: an example of this would be the metal copper.
2. Liquid: an example of this would be H2O or water.
3. Gas: an example of this would be oxygen gas or O2
4. Plasma: an example of this would be lightning.
hope this helps :)