The answer is A. waterfall
To be considered as an engine , it should be a Man-made objects that could be used to produce power that creates motions.
From all the options above could be used to produce such power, but the waterfall is not made by mandkind
A becuz its at da it dont got no wa
Answer:
The value of R and the internal resistance of the battery are 10.6 ohm and 2.45 ohm
Explanation:
Given that,
Emf of battery = 15.0 V
Voltage = 12.2 V
Power = 14.0 W
(a). We need to calculate the value of R
Using formula of power
Where, R = resistance
P = power
V = voltage
Put the value into the formula
(b). We need to calculate the internal resistance of the battery
Firstly we calculate the current
Using formula of current
Put the value of P and V into the formula
We calculate the internal resistance
Using formula of emf
Put the value into the formula
Hence, The value of R and the internal resistance of the battery are 10.6 ohm and 2.45 ohm
<span>v/2
This is an exercise in the conservation of momentum.
The collision specified is a non-elastic collision since the railroad cars didn't bounce away from each other. For the equations, I'll use the following variables.
r1 = momentum of railroad car 1
r2 = momentum of railroad car 2
x = velocity after collision
Prior to the collision, the momentum of the system was
r1 + r2
mv + m*0
So the total momentum is mv
After the collision, both cars move at the same velocity since it was non-elastic, so
r1 + r2
mx + mx
x(m + m)
x(2m)
And since the momentum has to match, we can set the equations equal to each other, so:
x(2m) = mv
x(2) = v
x = v/2
Therefore the speed immediately after collision was v/2</span>
The velocity of the combined mass after the collision is 0.84 ms-1.
<u>Explanation:</u>
According to law of conservation of momentum, the change in momentum before collision will be equal to the change in momentum of the objects after collision in isolated system.
But as it is perfectly inelastic collision in the present case, the final momentum will be based on the product of total mass of both the object with the velocity with which the collision occurred. This form is attained from the law of conservation of momentum as shown below:
So as law of conservation of momentum,
Here = 3 kg and = 2 kg are the masses of objects 1 and 2, = 1.4 m/s and = 0 are the initial velocities of object 1 and object 2, and are the final velocities of the objects.
So after collision, object 1 get sticked to object 2 and move together with equal velocity = = . Thus the above equation will become,
So the final velocity is
Thus,
= 0.84 ms-1.