Answer:
The type of wire
Explanation:
The EMF is induced in the closed conducting loop whenever there is a change in the magnetic flux linked with it. Mathematically, it is given by :
![\epsilon=\dfrac{-d\phi}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%3D%5Cdfrac%7B-d%5Cphi%7D%7Bdt%7D)
Where
is the magnetic flux
![\epsilon=\dfrac{-d(BA)}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%3D%5Cdfrac%7B-d%28BA%29%7D%7Bdt%7D)
For n number of coils,
![\epsilon=\dfrac{-d(NBA)}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%3D%5Cdfrac%7B-d%28NBA%29%7D%7Bdt%7D)
Where
B is the magnetic field
A is the area of the coil
If the coil is moved with the speed of v in the magnetic field, then induced EMF is given by :
![\epsilon=Blv](https://tex.z-dn.net/?f=%5Cepsilon%3DBlv)
l is the length of the coil
So, the induced EMF depends on the following factors:
- magnetic field
- velocity of the wire
- length of the wire in the field
So, the type of wire do not change the induced emf of the coil. Hence, the correct option is (b).