f(x) = (x - 2)^3 + 1
Find the derivative:-
f'(x) = 3(x -2)^2 This = 0 at the turning points:-
so 3(x - 2)^2 =
giving x = 2 . When x = 2 f(x) = 3(2-2)^3 + 1 = 1
Answer is (2, 1)
Answer:
your answer is c
Step-by-step explanation:
Answer:
8^-3 I think (i'm too lazy to simplify)
Step-by-step explanation:
3 - 9 * 2 ÷ 3 = ?
3 - 18 ÷ 3 = ?
3 - 6 = -3
8 to the power of -3
hmmmm i dont think im right tell me if im not
Step-by-step explanation:
I can't see the question your talking about
