Assuming you mean y = 200 - 16t^2, we have all the required information needed to solve this problem. The y-value is the height of the building and the t-value represents the number of seconds after the shoe fell off.
Since we are trying to solve <em>for t</em>, we will be using our y-value. The problem states that we landed on a building with a height of 31 feet. We can plug this into the y-value, since that is what y is defined as (the height of the building).
Now we have:
31 = 200 - 16t^2
We can solve this to find t:
-169 = -16t^2
169 = 16t^2
10.5625 = t^2
3.25, -3.25 = t
We have found two answers for t. However, the negative value is not a solution because we can not have a negative number of seconds. Thus, 3.25 is the only value of t which works for this problem.
Since t is the value we are trying to find, we have our answer. The shoe hits the building after 3.25 seconds.
The answer would be:
X = -1
Answer:
h - c +<u> c </u>= h
Step-by-step explanation:
Answer:
The answer is 42.
Step-by-step explanation:
5n - 13 = 42
5n = 42 + 13
5n = 55
n = 11
explanation about the solution = The angles formed by the segments measuring 42 and 5n - 13 are equal in measure which means the segments are as well.
15 grams
55 grams
0.005 kilograms
