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sergij07 [2.7K]
3 years ago
7

Write the standard form of the equation of the line that passes through point at (4,2) and is parallel to whose equation is y=2x

-4

Mathematics
1 answer:
solong [7]3 years ago
6 0
Since the equation is parallel to y=2x-4 that means they have the same slope. Now that you have the slope and fortunately a point, you can solve this by using point slope formula
y - y1 = m(x - x1)
Which is what I did on the attached picture and just rearrange it after solving to Ax+By=C/2x-y=6

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Stefen earns $88 in 8 hours. At this rate, how many dollars will he warn in 40 hours
Lina20 [59]

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6 0
4 years ago
HELP NEEDED!!!! MUCH APPRECIATED
jeka94

We have

t_1 + t+2 = \dfrac{\sqrt{s}}{4} + \dfrac{s}{1100} = .5

Multiplying through by 1100,

275 \sqrt{s} + s = 550

275 \sqrt{s} = 550 - s

Squaring (which means we need to check later),

275^2 s = (550 - s)^2 = 550^2 - 1100 s + s^2

0 = s^2 - (1100 + 275^2) s + 550^2

0 = s^2 - 76725 s + 302500

s = \frac 1 2 (76725 \pm 1375 \sqrt{3113} )

s \approx 3.94285 \textrm{ or } s \approx 76721.0571

Clearly there's no way that giant number would work; must be extraneous.

Answer: 3.94

Merry Christmas!

7 0
3 years ago
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