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sergij07 [2.7K]
3 years ago
7

Write the standard form of the equation of the line that passes through point at (4,2) and is parallel to whose equation is y=2x

-4

Mathematics
1 answer:
solong [7]3 years ago
6 0
Since the equation is parallel to y=2x-4 that means they have the same slope. Now that you have the slope and fortunately a point, you can solve this by using point slope formula
y - y1 = m(x - x1)
Which is what I did on the attached picture and just rearrange it after solving to Ax+By=C/2x-y=6

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I can’t figure out how to use the zeros in the polynomial. Please explain
Temka [501]

Answer:

a) P (x) = (x + 3) (x-1) (x-4)

b) P (x) = (2x + 5) (5x - 4) (x-6)

c) P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

P (x) = (x + 3) (x-1) (x-4)

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0

---------------------------------------

x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0

--------------------------------------

x = 6\\\\(x-6) = 0

--------------------------------------

P (x) = (2x + 5) (5x - 4) (x-6)

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

x = -3\\\\(x-3) = 0

--------------------------------------

x = 1\\\\(x-1) = 0

--------------------------------------

x = 4\\\\(x-4) = 0

----------------------------------------

x = -1\\\\(x + 1) = 0

-----------------------------------------

P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

8 0
3 years ago
3/4 divided by 5/6? i need the answer for this mobymax thing if i dont gets it done, im screwed
Dovator [93]
I believe it’s 0.9, or 9/10.
8 0
3 years ago
Hey guys I just wanted to put this out there-
tino4ka555 [31]

ok thank you so much for the info

5 0
3 years ago
Will mark brainliest
ikadub [295]

Answer:

3rd choice

Step-by-step explanation:

(7y^6)(2y^-4)^2

= (7y^6)(4y^-8)

Calculate:

(7y^6) * (4y^-8)

28y^-2

Express with a positive exponent:

28 * 1/y^2

8 0
3 years ago
I need help what is the answer to this question
spayn [35]

Answer: D

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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