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Ksenya-84 [330]
2 years ago
10

What is a reason for users and businesses to adopt 5G networks?

Computers and Technology
1 answer:
anzhelika [568]2 years ago
7 0

Answer:

I think users and businesses needs to adopt 5g networks for primary benefits include improved bandwidth, latency, reliability, connection density and security - all important factors in the increasing move to remote working and greater reliance on online services

Explanation:

sana po nakatulong

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What is a computer dedicated to a single function, such as a calculator or computer game? A. TabletB. PDAC.ApplianceD. Minicompu
viktelen [127]

Answer:

C. Appliance.

Explanation:

When a device or machine performs a single function or task, it is commonly referred to as an appliance. Examples of such is an iron, a calculator, a computer game, washing machines, refrigerators, e.t.c

<em>A Personal Digital Assistant (PDA)</em>, is a device, mostly mobile and handheld, that combines various computing features such as telephoning and networking. An example is a tablet. A PDA performs more than a single function.

<em>Minicomputer</em> is a computer usually small in physical size, that is midway in capabilities and support, between a microcomputer and a mainframe computer. An example is also a tablet and our smartphones. Minicomputers are also dedicated to various functions rather than a single function.

In summary, the option that best describes the situation in the question is an appliance.

<em>Hope this helps!</em>

6 0
3 years ago
You must receive an invitation in order to join Pinterest. True or False?
malfutka [58]
That is false, Pinterest is a free website that anyone can join!
3 0
3 years ago
Read 2 more answers
"Write a program that calculates the balance of a savings account at the end of a period of time. It should ask the user for the
Akimi4 [234]

Answer:

#include <iostream>

#include <fstream>

using namespace std;

int main() {

// Definitions

       double annualInterest;          // The annual interest rate

       double balance;                 // The account balance

       int months;                     // Total number of months

       double totalDeposit  = 0.0;     // Total deposited value

       double totalWithdraw = 0.0;     // Total withdrawn value

       double earnedInterest= 0.0;     // The earned amount

       double deposited;               // Monthly deposited value

       double withdrawn;               // Monthly withdrawn value

// Get the initial required data.

       

       cout<<"Please enter the annual interest rate,\n";

       cout<<"   Interest rate: ";

       cin >>annualInterest;

       cout<<"--------------------------------------------\n";

       cout<<"Please enter the starting balance,\n";

       do{

           cout<<"[the number could not be negative]\n";

           cout<<"Starting Balance: ";

           cin >>balance;

       }while(balance<0);

       cout<<"--------------------------------------------\n";

       cout<<"Please enter the number of months,\n";

       do{

           cout<<"[the number could not be less than 0]\n";

           cout<<"Number of months: ";

           cin >>months;

       }while(months<0);

// Iterated Loop to get all the months data.

       for(int month=1; month <= months; month++){

// Get the deposited value during that month.

           cout<<"Enter the deposited value during month "

               <<month<<",\n";

           do{

               cout<<"[the value could not be less than 0]\n";

               cout<<" Deposited value: ";

               cin >>deposited;

           }while(deposited<0);

           

           totalDeposit += deposited;

           balance += deposited;

// Get the withdrawn value during that month.

           cout<<"Enter the withdrawn value during month "

               <<month<<",\n";

           do{

               cout<<"[the value could not be less than 0]\n";

               cout<<" Withdrawn value: ";

               cin >>withdrawn;

           }while(withdrawn<0);

           

           totalWithdraw += withdrawn;

           balance -= withdrawn;

// Negative balance close the program.

           if(balance < 0){

               cout<<"Sorry, the account has been closed due to\n";

               cout<<"the negative balance.\n";

                 break;

// Calculate value due to the interest rate.

           }

      else {

               earnedInterest += (annualInterest/12) * balance;

               //        monthly interest rate

               balance += (annualInterest/12) * balance;

           }

       }

  // Display the statistics,

      ofstream file;

      file.open ("Report written to Report.txt");

      file << "Report written to Report.txt\n";

       file.close();

       cout<<"The ending balance: "<<balance<<std::endl;

       cout<<"   Total deposited: "<< totalDeposit<<std::endl;

       cout<<" Total withdrawals: "<< totalWithdraw<<std::endl;

       cout<<"   Earned interest: "<< earnedInterest<<std::endl;

       cout<<"============================================\n";

 return 0;

   }

   

6 0
3 years ago
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
Match each code snippet to its appropriate markup language name
Mazyrski [523]

Answer:

Please find the complete solution in the attached file.

Explanation:

8 0
3 years ago
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