Answer:
A-because most of the victims of intellectual theft are individuals
Explanation:
Its definitely the first, and not B., C, or D,
Countries are no barrier in catching the theft, as almost all the countries now have issued the online identification number of each of their citizens. However, some of them are in the process. Hence, for next one - two years we can add add the B as well:
B-because much intellectual theft is committed in other countries
However, as this work is complete, the B option will not be an issue related to intellectual theft analysis and control.
And C and D are definitely not the part of the answer, as associations like FCC USA, Internet association etc are technically sound enough, and quite good to fight a case under any law as well.
10.......................................
Answer:
Step 1: Visit iCloud.com and log in with your Apple ID and password
At the same time, a window also pops up on iDevice
you need to click "Allow"
Copy the code from your phone to icloud.com
Step 2: Once signed in, select Settings on homepage
Step 3: Click "Manage" Apple ID.
Step 4: You will be directed to another site – appleid.apple.com
input your password to log in and verify it with Apple ID verification code.
Step 5: Then you will enter the manage page.
Click "Edit" in Security column.
Step 6: Click "Turn Off Two-Factor Authentication"
then confirm it.
Step 7: Then you need to select your security questions and answer them
click "Continue" after confirming your birthday and rescue email.
After all of these steps, you have turned off two factor authentication for Apple ID successfully.
Source : https://www.imobie.com/guide/anytrans/how-to-turn-off-two-step-verification-in-icloud.htm
A.Information on social networking sites can give most or all digits of a person’s social security number.
Answer:
The code is not dereferencing the pointers. You have to place an asterisk in front of the pointer to read the value the pointer points to.
Explanation:
So "if (str1 != str2)" must be "if (*str1 != *str2)".
likewise:
while (*str1 != 0 && *str2 != 0)
and
result = (*str1 == *str2);
