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Kryger [21]
3 years ago
7

Ian kno da answer tell me

Computers and Technology
2 answers:
kirill115 [55]3 years ago
7 0

Answer:

b

Explanation:

sammy [17]3 years ago
6 0
B is the answer.....
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sergejj [24]

Answer:

they arent made to Express emotion? can you be a little more specific with the question?

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3 years ago
Question 2 of 10
horrorfan [7]

Answer:

Lowest Level; Machine Language.

Explanation:

The lowest level of a computer is machine language, which are strings of 0's and 1's in bits, and it's possible to perform tasks at this level. It's however difficult to do and humans created <em>Assembly</em>; a type of low level programming language to be readable, and converts to machine language so that we don't have to work in binary.

4 0
2 years ago
Write an algorithm that prints out all the subsets of 3 elements of a set of n elements. The elements of the set are stored in a
Ksenya-84 [330]

void Print_3_Element_Subsets(int n,const element_type S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

print("No subset found");

}

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

print(S[i],S[j],S[k]);

}

}

}

}

C++ Implementation;

#include<cstdlib>

#include<time.h>

using namespace std;

int S1[5]= {1,2,3,4,5};

int n1 = 5;

int S2[2]={1,2};

int n2 = 2;

void Print_3_Element_Subsets(int n,const int S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

printf("No subset found\n");

}

printf("3 Subsets are\n");

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

cout<<S[i]<<" "<<S[j]<<" "<<S[k]<<endl;

}

}

}

}

int main()

{

cout<<"Case 1"<<endl;

Print_3_Element_Subsets(n1,S1);

cout<<endl<<"Case 2"<<endl;

Print_3_Element_Subsets(n2,S2);

}

OUTPUT

Case 1

3 Subsets are

1 2 3

1 2 4

1 2 5

1 3 4

1 3 5

1 4 5

2 3 4

2 3 5

2 4 5

3 4 5

Case 2

No subset found

3 Subsets are

--------------------------------

Process exited after 0.0137 seconds with return value 0

Press any key to continue . . .

7 0
3 years ago
What is the e-file rejection error for an Invalid bank account or routing transit numbers?
dezoksy [38]
Usually when you encounter the problem you see the error code number "0019" for an invalid bank account or routing transit numbers.

Accounting information is the subject to which this is categorized. As soon as the IRS or (Internal Revenue Service) suspects any error, it will deny the return immediately. 
3 0
3 years ago
Write a function that receives two numbers, m and n and calculates and displays the sum of the integers from m to n. For example
Evgesh-ka [11]

Answer:

The program to this question as follows:

Program:

//header file

#include <stdio.h> //defining header file

void inc(int m,int n) //defining method inc

{

   int sum, i; //declaring variable

   sum=m; //holding value of m variable

   for(i=++m;i<=n;i++) //loop for calculate number between given range  

   {

   sum=sum+i; //adding value

   }

   printf("sum of the integer is : %d",sum);//print value

}

int main() //defining method

{

   int m,n; //defining integer variable

   printf("Enter m value: "); //message

   scanf("%d",&m); //input value by user in variable

   printf("Enter n value: "); //message

   scanf("%d",&n);//input value by user in variable

   inc(m,n); //calling method

   return 0;

}

Output:

Enter m value: 3

Enter n value: 7

sum of the integer is :25

Explanation:

In the above code, an "inc" function is declared, that accepts integer parameters that are "m and n", inside the method two integer variable "sum and i" is declared, which is used in the loop.

  • The loop uses the user parameter to count value and uses the sum variable to calculate there sum.
  • In the main method, two integer variable n and m are declared, which take value from the user end, and at the last, we call the inc method, that prints sum value.
7 0
2 years ago
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