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denis-greek [22]
2 years ago
14

0.4 divided by 41 (help pls-

Mathematics
2 answers:
sasho [114]2 years ago
8 0
102.5

Lol, well to start, it’s not asking to divide 0.4 by 41. It’s asking to divide 41 by 0.4.
And that will get you to 102.5. You could do long division or use a calculator if you are allowed.
nexus9112 [7]2 years ago
3 0
The answer is to your question is 102.5
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-5x+y=6<br> -3x+6y=-12<br> Solving systems of equations by substitution
Yakvenalex [24]

if you isolate y in the top equation to get y=5x+6 then you can substiture y for 5x+6 in the bottom equation because thats what y equals

as of now you have -3x+6(5x+6)=-12 but if you use the distrubite property you would get -3x+30x+36=-12

then if you subtract 36 from both sides you would get -3x+30x=-48 then combine like terms to get 27x=-48 then divide both sides by 27 to get x=\frac{-48}{27} or x≈1.8

4 0
3 years ago
a 120 watt light bulb uses about 0.1 kilowatt of electricity per hour. if electricity costs 0.20 per kilowatt hour, how much doe
Allushta [10]
A 120 watt light-bulb is a 0.120 kilowatt light bulb.

In one hour, it uses 0.120 kilowatt-hour of energy.

If electrical energy costs $0.20 per kilowatt hour, then that light bulb costs

        (0.120 kilowatt-hour / hour) x (0.20 dollar / kilowatt-hour) =

                            (0.120 x $0.20 / hour)  =  

                                       $0.024 / hour  =  <span>2.4¢  per hour </span>
5 0
3 years ago
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
There are 29235 marbles and 371 jacks. If you want to know the percentage of jacks, do you divide the first number by the second
garik1379 [7]

Answer:

Correct answer: Two decimal places to the right

Step-by-step explanation:

We will set the classic proportion:

29,235   -    100%

     371    -        x%

29,235 : 371 = 100 : x  ⇒ 29,235 · x = 371 · 100

x = (371/ 29,235) · 100 = 0.0127 · 100 = 1.27%

x = 1.27%

You divide first number by the second and then multiply with 100,

which is the same as moving the decimal point two places to the right.

God is with you!!!

3 0
3 years ago
3.14(a2 + ab) when a = 4 and b = 2.
Debora [2.8K]
Just replace a with 4 and b with 2 and your equation looks like
3.14 (4×2+4×2)
solve within the parenthesis first
3.14 (8+8)
3.14 (16) =50.24
5 0
3 years ago
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