The population of the fish is given by P(t) = 750(1 + 0.083)^t; where t is the number of years after 2005.
Here, t = 2050 - 2005 = 45
Population in 2050 = 750(1.083)^45 = 750(36.16) = 27,123
the answer is C................................
I hope this helps you
10B=6-12C
B=2 (3-6C)/10
B =3-6C/5
Answer:
49pi, or 153.93
Step-by-step explanation:
pi*r^2=Area
14/2=7=r
r^2=7^2=49
Answer:49pi or 153.93
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