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kirill [66]
3 years ago
11

Mangoes cost $4 each and nectarines cost $2 each. Dominic buys m mangoes and n nectarines for $32.

Mathematics
1 answer:
xenn [34]3 years ago
5 0

Answer: 6m+4n=32

Step-by-step explanation:

m=4

n=2

From this, we can deduce that m+n=32.

6*4=24 and 4*2=8. 24+8=32

So, 6m+4n=32. Hope this was what you were looking for!

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klemol [59]

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Step-by-step explanation:

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2 years ago
Carrie walks 525 feet from her house to jay's house. Then, she walks another 280 feet in the same direction to Asia's house. Whi
earnstyle [38]

Answer:

The answer should be 525

7 0
3 years ago
A cable TV company charges $25
olga nikolaevna [1]

Answer:

D

Step-by-step explanation:

75=(4*25)=C

  • it means 25*3 which is the new price for the Fifth month should be equal to 75
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2 years ago
Two isosceles triangles share the same base. Prove that the medians to this base are collinear. (There are two cases in this pro
Anna71 [15]

Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

→Case 1.  When vertices A and P are opposite side of Base BC.

In Δ ABD and Δ ACD

AB= AC   [Given]

AD is common.

BD=DC  [median of a triangle divides the side in two equal parts]

Δ ABD ≅Δ ACD [SSS]

∠1=∠2 [CPCT].........................(1)

Similarly, Δ PBD ≅ Δ PCD [By SSS]

 ∠ 3 = ∠4 [CPCT].................(2)

But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

2 ∠2 + 2∠ 4=360° [using (1) and (2)]

∠2 + ∠ 4=180°

But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.

So, point A, D, P lies on a line.

CASE 2.

When ΔABC and ΔPBC lie on same side of Base BC.

In ΔPBD and ΔPCD

PB=PC[given]

PD is common.

BD =DC [Median of a triangle divides the side in two equal parts]

ΔPBD ≅ ΔPCD  [SSS]

∠PDB=∠PDC [CPCT]

Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

∴ P,A,D lie on a line i.e they are collinear.




3 0
3 years ago
What is the smallest number of parts that a rectangle could be divided into compare fractions of 5/8 and 3/4
Mashutka [201]
You would have to multiply the top and bottom of both fractions, to get equal number between them,
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