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3 years ago

Mangoes cost $4 each and nectarines cost $2 each. Dominic buys m mangoes and n nectarines for $32.

Mathematics

1 answer:

xenn [34]3 years ago

5 0

Answer: 6m+4n=32

Step-by-step explanation:

m=4

n=2

From this, we can deduce that m+n=32.

6*4=24 and 4*2=8. 24+8=32

So, 6m+4n=32. Hope this was what you were looking for!

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50 points!!!Adam recorded the number of flower blooms on each of his ten rose bushes. 9, 10, 4, 12, 15, 17, 18, 10, 12, 13If he

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Answer:

Step-by-step explanation:

9, 10, 4, 12, 15, 17, 18, 10, 12, 13

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The median is the middle number

There are 10 numbers

4,9, 10, 10, 12 12, 13, 15, 17, 18,

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3 years ago

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A rental car company charges $77. 50 per day to rent a car and $0. 14 for every mile

muminat

77.5d + .14m

m = 425

.14 * 425 = 59.5

77.5d + 59.5 ≤ 230

77.5d ≤ 170.5

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2 years ago

HURRY 40 POINTS !!!!!!!!! A person runs 1/4 of a mile in 1/32 of an hour. Compute the unit rate by setting up a complex fraction

hram777 [196]

I am not sure, but the best answer should be 8 miles per hour

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3 years ago

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Quincy sold three times as many magazines as Olivia. Trenton sold two less than twice the number of magazines that Quincy sold.

Anastaziya [24]

Olivia sold 14 magazines.

Step-by-step explanation:

Total magazines sold = 138

Let,

Magazines sold by Olivia = x

Magazines sold by Quincy = y

Magazines sold by Trenton = z

According to given statements;

x+y+z=138 Eqn 1

Quincy sold three times as many magazines as Olivia.

y = 3x Eqn 2

Trenton sold two less than twice the number of magazines that Quincy sold.

z = 2y-2 Eqn 3

Putting value of y from Eqn 2;

$z=2(3x)-2\\z=6x-2\ \ \ \ Eqn\ 4$

Putting value of y from Eqn 2 and value of z from Eqn 3 in Eqn 1

$x+3x+(6x-2)=138\\4x+6x-2=138\\10x=138+2\\10x=140\\$

Dividing both sides by 10

$\frac{10x}{10}=\frac{140}{10}\\x=14$

Olivia sold 14 magazines.

Keywords: linear equations, division

Learn more about division at:

#LearnwithBrainly

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3 years ago

Will give brainliest! pts to the correct answer! Are quadratic equations already in rectangular form? I'm asked to eliminate th

Semmy [17]

$\bf x(t)=0.5t^2+0.4t-87.30\implies x(t)=\cfrac{1}{2}t^2+\cfrac{2}{5}t-\cfrac{873}{10}
\\\\\\
x=\cfrac{1}{2}\left( t^2+\cfrac{4}{5}t+\boxed{?}^2 \right)-\cfrac{873}{10}$

so, as you already know, we'll borrow from our good friend Mr Zero, 0, to get that missing value for the perfect square trinomial,

$\bf x=\cfrac{1}{2}\left[ t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2-\left( \cfrac{2}{5} \right)^2 \right]-\cfrac{873}{10}
\\\\\\
x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\cfrac{4}{25}-\cfrac{4}{25} \right]-\cfrac{873}{10}
\\\\\\
x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2\right]-\cfrac{2}{25}-\cfrac{873}{10}
\\\\\\
x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2\right]-\cfrac{4369}{50}$

$\bf x=\cfrac{1}{2}\left( t+\frac{2}{5} \right)^2-\cfrac{4369}{50}\implies x+\cfrac{4369}{50}=\cfrac{1}{2}\left( t+\frac{2}{5} \right)^2
\\\\\\
2x+\cfrac{4369}{25}=\left( t+\frac{2}{5} \right)^2\implies \sqrt{2x+\cfrac{4369}{25}}=t+\cfrac{2}{5}
\\\\\\
\sqrt{2x+\cfrac{4369}{25}}-\cfrac{2}{5}=t$

$\bf -------------------------------\\\\
y(t)=0.4t^2+0.1t+29.44\implies y=\cfrac{2}{5}t^2+\cfrac{1}{10}t+\cfrac{736}{25}
\\\\\\
y=\cfrac{2}{5}\left( \sqrt{2x+\cfrac{4369}{25}}-\cfrac{2}{5} \right)^2+\cfrac{1}{10}\left( \sqrt{2x+\cfrac{4369}{25}}-\cfrac{2}{5} \right)+\cfrac{736}{25}$

4 0

3 years ago