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Katena32 [7]
3 years ago
9

a baker used 660 boxes of cake mix to make a wedding cake. if each box called for 3 eggs, how many dozen eggs were used to make

the wedding cake?​
Mathematics
1 answer:
yanalaym [24]3 years ago
6 0
We know there’s 660 boxes and each box called for 3 eggs, therefore:

660=3X

when divide both sides by 3 to isolate the x, which will tell us the amount of eggs used…

660/3 = 220
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Step-by-step explanation:

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Given the diagram below, which pair of lines
Olenka [21]

Answer:

b

Step-by-step explanation:

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3 years ago
Consider the system of equations.
anzhelika [568]

Answer: You can multiply the top equation by -1 to eliminate the x variable.

And the solution is (2,4/3)  in case you need it.

Step-by-step explanation:

2x + 3y = 8

2x + 6y = 12

If you multiply the upper equation or down equation by one, you will be able to eliminate the x variable.

-1( 2x + 3y) = -1(8)     New equation:   -2x -3y  = -8.

Add the new equation you got  by multiplying the top equation by -1 to the bottom equation.

Add them:     -2x -3y = -8

                      2x + 6y = 12  

                               3y = 4  

                              y = 4/3

You can now input the value for y into the one of the equations and solve for x.

-2x - 3(4/3) = -8

-2x -4 = -8  

     +4     +4

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8 0
3 years ago
A shoe manufacturer was investigating the weights of men's soccer cleats. He felt that the weight of these cleats was less than
aleksklad [387]

Answer:

 The conclusion is that the researcher was correct

Step-by-step explanation:

From the question we are told that

     The sample size is  n =  13

    The sample mean is  \= x =  9.63

     The standard deviation is  s =  0.585

      The significance level is  \alpha  =  0.05

The Null Hypothesis is  H_o :  \mu = 0

The Alternative  Hypothesis  is  H_a =  \mu < 10

The test statistic is  mathematically represented as

          t =  \frac{\= x - \mu }{\frac{s}{\sqrt{n} } }

Substituting values

          t =  \frac{9.63  - 10 }{\frac{0.585}{\sqrt{13} } }

         t =  -  2.280

Now the critical value for \alpha is  

     t_{\alpha } = 1.645

This obtained from the critical value table

  So comparing the critical value of alpha and the test value we see that the test value is less than the critical value so the Null Hypothesis is rejected

 The conclusion is that the researcher was correct

 

 

6 0
4 years ago
Can a sequence be both arithmetic and geometric?
artcher [175]
An aritmetic sequence is like this
a_n=a_1+d(n-1) where a1=first term and d=common difference

geometric is a_n=a_1(r)^{n-1} where a1=first term and r=common ratio


can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same

therfor we need to solve d(n-1)=(r)^{n-1}
what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?

when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal

the answer is no, a sequence cannot be both aritmetic and geometric
4 0
3 years ago
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