Answer:
Sure i will buy them, where you live so i can pay fro estimated shipping
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
Answer: You can multiply the top equation by -1 to eliminate the x variable.
And the solution is (2,4/3) in case you need it.
Step-by-step explanation:
2x + 3y = 8
2x + 6y = 12
If you multiply the upper equation or down equation by one, you will be able to eliminate the x variable.
-1( 2x + 3y) = -1(8) New equation: -2x -3y = -8.
Add the new equation you got by multiplying the top equation by -1 to the bottom equation.
Add them: -2x -3y = -8
2x + 6y = 12
3y = 4
y = 4/3
You can now input the value for y into the one of the equations and solve for x.
-2x - 3(4/3) = -8
-2x -4 = -8
+4 +4
-2x = -4
x = 2
Answer:
The conclusion is that the researcher was correct
Step-by-step explanation:
From the question we are told that
The sample size is 
The sample mean is 
The standard deviation is 
The significance level is 
The Null Hypothesis is 
The Alternative Hypothesis is 
The test statistic is mathematically represented as

Substituting values


Now the critical value for
is

This obtained from the critical value table
So comparing the critical value of alpha and the test value we see that the test value is less than the critical value so the Null Hypothesis is rejected
The conclusion is that the researcher was correct
An aritmetic sequence is like this

where a1=first term and d=common difference
geometric is

where a1=first term and r=common ratio
can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same
therfor we need to solve

what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?
when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal
the answer is no, a sequence cannot be both aritmetic and geometric