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3 years ago

The value of P where P= (1)2 + (3)2 + (5)2 +......... + (25)?

Mathematics

1 answer:

kramer3 years ago

6 0

Answer:

338

Step-by-step explanation:

1×2=2 2+6+10+14+18+22+26+30

3×2=6 +34+36+38+42+46+50=338

5×2=10

7×2=14

9×2=18

11×2=22

13×2=26

15×2=30

17×2=34

19×2=38

21×2=42

23×2=46

25×2=50

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Answer:

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Step-by-step explanation:

f(x) = 3x + 1
f(7) = 3(7) + 1
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<u>Or if the equation meant it like this:</u>

f(x) = 3x + 1
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A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

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Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

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You subtract 16 from each side of the equation.
Then it will say exactly what number 'n' is.
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