All categories

2 years ago

4x+5t = 225x - t = 13 what is x and t

Mathematics

1 answer:

Anton [14]2 years ago

5 0

Answer:

5(5x-t)

=13×5

25x - 5t

=65

25x -5t + 4x +5t

=65 + 22

29x

= 87

= 87÷29

x =3

substituting x=3 in 5x-t=13

15- t

=13

15 - 13

= t

t = 2

Step-by-step explanation:

You might be interested in

Find the end time.<br> Start time: 11:35 AM.<br> Elapsed time: 3 hr 10 min<br> End time _____ P.M.

Zina [86]

Answer:

2:45 PM

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

3 years ago

Seven apple women possessed respectively 20,40,60,80,100,120,and 140 apples, went to market and sold all their apples at the sam

ra1l [238]

Answer: Each woman sold her apples at the rate of seven apples for I¢, and 3¢ each for the odd ones which were left over. this made it possible for each to receive the same amount, which is 20¢.

Step-by-step explanation:

given data:

20,

40,

60,

80,

100,

120,

140.

solution.

first woman 20 apples

= 2 + 3 * 6¢.

= 20¢.

second woman 40 apples

= 5 + 5 * 3¢.

= 20¢.

third woman 60 apples

= 8 + 4 * 3¢.

= 20¢.

fourth woman 80 apples

= 11 + 3 * 3¢.

= 20¢.

fifth woman 100 apples

= 14 + 2 * 3¢.

= 20¢.

sixth woman 120 apples

= 17 + 1 * 3¢.

= 20¢.

seventh woman 140 apples

= 20 * 1¢.

= 20¢.

3 0

3 years ago

Can Someone help and explain how to get this answer?

Kay [80]

44%
42%
78%
21%
30%
8%
i calculated everything

8 0

2 years ago

Read 2 more answers

15x3 - 5x²y + 5xy, factorization<br>

Dominik [7]

5•3•x•x•x-5•x•x•y+5•x•y=
5x(3x^2-xy+y)
Hope this explanation helps

7 0

2 years ago

4x+5t = 225x - t = 13 what is x and t ​

4x+5t = 225x - t = 13 what is x and t