<CAB=<CDE, AC=4cm, DC=5cm and DE=7cm. Determine the length of sides AB of ∆ABC.

A shipment of 40 fancy calculators contains 3 defective units. What is the probability if a college bookstore buys 20 calculator

JulsSmile [24]

Answer:

38.46%

Step-by-step explanation:

There are no names or marking that can make the calculator look different, so the order is not important. Then we should use a combination to solve this problem.

There are 40 calculators in one shipment, 37 of them good items and 3 of them are defect items. We need to choose 19 good calculators and 1 defect calculator. The number of ways to do that will be:

$\frac{37}{19}$ * $\frac{3}{1}$ = 37! $\frac{37!}{19!(37-19!)} * \frac{3!}{1!(3-1)!}$ = 53017895700

The number of possible ways to choose 20 calculators out of 40 calculators will be:

$\frac{40}{20}$ = $\frac{40!}{20!(40-20!)}$ =137846528820

The chance will be: 53017895700/ 137846528820 = 0.3846= 38.46%

4 0

3 years ago

Please someone help, I know its kind of a lot, but I need these answers fast pls.

Dmitry_Shevchenko [17]

Answer:

Im not sure

Step-by-step explanation:

GOOD LOOK ON YOUR TEST HE DISCONN-ECTED

5 0

3 years ago

A manufacturer of nails claims that only 4% of its nails are defective. A random sample of 20 nails is selected, and it is found

irakobra [83]

Answer:

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

A manufacturer of nails claims that only 4% of its nails are defective.

At the null hypothesis, we test if the proportion is of 4%, that is:

$H_0: p = 0.04$

At the alternative hypothesis, we test if the proportion is more than 4%, that is:

$H_a: p > 0.04$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

4% is tested at the null hypothesis

This means that $\mu = 0.04, \sigma = \sqrt{0.04*0.96}$

A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective.

This means that $n = 20, X = 0.1$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.1 - 0.04}{\frac{\sqrt{0.04*0.96}}{\sqrt{20}}}$

$z = 1.37$

P-value of the test and decision:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

Looking at the z-table, z = 1.37 has a p-value of 0.9147

1 - 0.9147 = 0.0853

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

7 0

2 years ago

Read 2 more answers

What is the answer to 6x> -54

Anestetic [448]

Answer:

6 times whatever x is would be greater that -54

7 0

3 years ago

Sharon suspects that her brother's penny is unfair. She flips it 50 times and heads comes up 40 times. Based on these trials, th

cricket20 [7]

The correct answer is B. 4/5. Hope this helps! : )

6 0

3 years ago

Read 2 more answers

<CAB=<CDE,AC=4cm, DC=5cm andDE=7cm. Determine thelength of sides AB of∆ABC.​

<CAB=<CDE,AC=4cm, DC=5cm andDE=7cm. Determine thelength of sides AB of∆ABC.