All categories

2 years ago

What is 4.87 x 7.23 (show ur work)

Mathematics

1 answer:

rewona [7]2 years ago

5 0

Answer:

the answer is 35.2101 explained in image .

You might be interested in

There are 6 boys and 9 girls in the church's youth group. What type of ratio is boys to girls

mina [271]

I hope this helps you

6/9

2.3/3.3

2/3

2:3

3 0

3 years ago

How many numbers are between 1 and 3 ?

kramer

If we are talking about whole numbers, the only number in between 1 and 3 is 2 but if we are talking about numbers in general, there are an infinite amount of numbers (for example, 1.1, 1.12, 1.004, and 1.80543285 are all in between 1 and 3).

5 0

3 years ago

Yvette earns $3 for every 1/4 hour she works. what is her hourly rate of pay

Lunna [17]

Yvette's hourly rate of pay is $12.
3+3+3+3=12

7 0

3 years ago

Paula caught a tarpon with a weight that was 10 times as great as the weight of a permit fish she caught . The total weight of t

olya-2409 [2.1K]

X equals weight of permit fish
x + 10X = 132
11x = 132
x= 12

permit fish= 12
tarpon=120

7 0

3 years ago

Read 2 more answers

What is an example of when you would want consistent data and, therefore, a small standard deviation?

steposvetlana [31]

Answer:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

$\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271$

And for the standard deviation we can use the following formula:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And after replace we got:

$s = 0.1496$

And as we can ee we got a small value for the deviation <1 on this case.

Step-by-step explanation:

For example if we have the following data:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

We see that the data are similar for all the observations so we would expect a small standard deviation

If we calculate the sample mean we can use the following formula:

$\bar X=\frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271$

And for the standard deviation we can use the following formula:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And after replace we got:

$s = 0.1496$

And as we can ee we got a small value for the deviation <1 on this case.

8 0

3 years ago