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Thepotemich [5.8K]
4 years ago
14

Noah and his friends are going to an amusement park. The total cost of admission for 8 students is $100, and all students share

the cost equally. Noah brought $13 for his ticket. Did he bring enough money to get into the park explain you reasoning.
Mathematics
2 answers:
Lana71 [14]4 years ago
8 0

Answer:

The correct answer is yes, he brought enough money to get into the park.

Step-by-step explanation:

Well, let's analyze the information provided:

Admission to the amusement park for 8 students is $ 100. If each student agreed to share of cost equally, it means that we must divide those 100, for each of those students.

Therefore it will remain 100/8 = 12.5

<u>If each student must pay 12.5</u>, and <u>Noah brought $ 13</u>, that means he will have enough money to enter the park, and he will even have $ 0.50 left over.

aliina [53]4 years ago
6 0
Yes, if all 8 of the students shared the cost of $100 dollars equally, that would mean each student paid $12.50.
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A student at a four-year college claims that average enrollment at four-year colleges is higher than at two-year colleges in the
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Answer:

a) Since we have sample data and we don't know the population deviation we can use the t distribution in order to test the hypothesis

t would represent the statistic

b) t=\frac{(\bar X_{2}-\bar X_{1})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)  

The degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  Replacing the info given we got:

t=\frac{(5216-5069)-0}{\sqrt{\frac{4773^2}{35}+\frac{8141^2}{35}}}}=0.0921  

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Since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean of enrollment is significantly higher for four year college than for two year college

Step-by-step explanation:

Information given

\bar X_{1}=5069 represent the mean for two year colleges

\bar X_{2}=5216 represent the mean for four year college

s_{1}=4773 represent the sample standard deviation for 1  

s_{2}=8141 represent the sample standard deviation for 2  

n_{1}=35 sample size for the group 2  

n_{2}=35 sample size for the group 2  

\alpha=0.05 Significance level provided

Part a

Since we have sample data and we don't know the population deviation we can use the t distribution in order to test the hypothesis

t would represent the statistic

Part b

We want to test if the mean of enrollment for four year college is higher than for two year college, the system of hypothesis would be:  

Null hypothesis:\mu_{2}-\mu_{1} \leq 0  

Alternative hypothesis:\mu_{2} - \mu_{1} > 0  

The statistic is given by:

t=\frac{(\bar X_{2}-\bar X_{1})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)  

The degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  Replacing the info given we got:

t=\frac{(5216-5069)-0}{\sqrt{\frac{4773^2}{35}+\frac{8141^2}{35}}}}=0.0921  

Part c

The p value would be given by:

p_v =P(t_{68}>0.0921)=0.463  

Since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean of enrollment is significantly higher for four year college than for two year college

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