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Vaselesa [24]
3 years ago
9

Distinguished between

Computers and Technology
1 answer:
VladimirAG [237]3 years ago
4 0

Answer:

this one is not understandable you see but I think it's better than nothing to do with it tmzr I don't know what to say to someone who did you start the morning and you can not be able to get it to

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You're creating a table for one of your slides, and need to make some modifications to your table structure. Which of the follow
sdas [7]
A. is the correct answer
6 0
3 years ago
Discuss trends in cellular data transmission speeds
Nimfa-mama [501]

Answer:

  There are various types of cellular data with the different transmission speeds that are: 1G,2G,3G and 4G.

1st generation network:

The 1st generation network is known as cellular network data transmission that contain analog system. It has 2.4kbps speed range. It is widely used in various services like public voice.

 2nd generation network:

The second generation network is basically based on the digital system. The global positioning system (GSM) is one of the important service in the 2nd generation network. It basically provide different types of services that are:

    GSM provide upto 2.5G range of speed and GSM EDGE upto 23kbps services.

 3rd generation network:

 It the wireless service that is basically based on the digital system. It provide various types of services like mobile interne, video calling and wireless type of telephones.

  4th generation network:

 It is one of the high digital data transmission rate and it is basically represented as the LTE.  The 4G provide many types of services like  multimedia services and telephone and gaming services.

5 0
3 years ago
Read 2 more answers
you manage a network that has multiple internal subnets. you connect a workstation to the 192.168.1.0/24 subnet. this workstatio
nydimaria [60]

Based on the configuration written below, the most likely cause of the problem is Incorrect subnet mask.

<h3>What is an Incorrect Subnet Mask?</h3>

The issue of an Incorrect Subnet Mask will take place if a network uses a subnet mask that is not theirs for its address class, and a client is still said to be configured with the same default subnet mask for the address class, and thus communication tend to fail to some closeby networks.

Therefore, Based on the configuration written below, the most likely cause of the problem is Incorrect subnet mask.

Learn more about subnet mask from

brainly.com/question/27418272

#SPJ1

See full question below

You manage a network that has multiple internal subnets. You connect a workstation to the 192.168.1.0/24 subnet.

This workstation can communicate with some hosts on the private network, but not with other hosts. You run ipconfig /all and see the following:

Ethernet adapter Local Area Connection: Connection-specific DNS Suffix . : mydomain.local Description . . . . . . . : Broadcom network adapter Physical Address. . . . . . : 00-AA-BB-CC-74-EF DHCP Enabled . . . . . . . : No Autoconfiguration Enabled. . . : Yes IPv4 Address . . . . . . . : 192.168.1.102(Preferred) Subnet Mask. . . . . . . . : 255.255.0.0 Default Gateway . . . . . . : 192.168.1.1 DNS Servers . . . . . . . : 192.168.1.20 192.168.1.27

What is the most likely cause of the problem?

8 0
1 year ago
Changing how information is represented so that it can be read by a computer is called
Jobisdone [24]

Answer:

Your answer is D) Encode

Explanation:

Definition of Encode: To change how information is represented so that it can be read by a computer.

7 0
3 years ago
Complete the following Programming Assignment using Recursion. Use good programming style and all the concepts previously covere
Likurg_2 [28]

Answer:

Explanation:

public class Ackermann {

   public static int ackermann's(int m, int n) {

       if (m == 0) {

           return n + 1;

       } else if (n == 0) {

           return ackermann's(m-1, 1);

       } else {

           return ackermann(m - 1, ackermann(m, n - 1));

       }

   }

   public static void main(String[] args) {

       System.out.println(ackermann(0, 0));

       System.out.println(ackermann(0, 1));

       System.out.println(ackermann(1, 1));

       System.out.println(ackermann(1, 2));

       System.out.println(ackermann(1, 3));

       System.out.println(ackermann(2, 2));

       System.out.println(ackermann(3, 2));

   }

}

1

2

3

4

5

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7

29

Process finished with exit code 0

6 0
3 years ago
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