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Svetlanka [38]
3 years ago
10

I need help with this please?

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0
A. since they choose 4 people to form the committee and all the people chosen are teachers
from 5 teacher, we choose 4, 5C4
and
from 20 parents, we choose none, 20C0
5C4*20C0= 5

b. from 5 teacher choose 2, 5C2
and
from 20 parents choose 2, 20C2

5C2 * 20C2=1900

c.all parents
from 5 teachers choose 0, 5C0
and
from 20 parents choose 4, 20C4

5C0 * 20C4= 4845

d. from 5 teacher choose 1, 5C1
and
from 20 parents choose 3, 20C3

5C1 * 20C3= 5700
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In the previous problem, which of the following is m angle B to the nearest degree?
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Answer:

A. 30

Step-by-step explanation:

sin theta = opposite side / hypotenuse

sin B = 8/16

sin B = 1/2

Take the arcsin of each side

arcsin sin(B) = arcsin (1/2)

B = arcsin (1/2)

B = 30

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3 years ago
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3 years ago
Find the median of 30 , 40, 35, 50 and 55 degrees angle measures
ELEN [110]
We know that
the median <span>is the middle number when listed in order from least to greatest.
</span>
step 1
listed in order from least to greatest
[<span>30,40, 35, 50, 55]--------> [30, 35, 40, 50, 55]

step 2
find the middle number

the middle number is 40

therefore

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the median is 40</span>°<span>

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6 0
3 years ago
PLZ HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Andreyy89

Answer:

Step-by-step explanation:

9 * 9 * h = 1620. Isolate the variable. h = 20. The equation would be 9*9*20 or 9^2*20.

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3 years ago
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I WILL GIVE BRAINLIST IF ALL ANSWERED CORRECTLY
pentagon [3]

Answer:

The length of the track is approximately 51.7 ft

The track has three sides of the square and the distance round a half of a complete circle

Step-by-step explanation:

The given track shape and measurements are;

The shape on the left side of the track  = Square

The shape on the right side of the track  = Half circle

The area of the square on the the left side of the track  = 128 square feet

Therefore, from the area, A, of a square of side length, s, which is s × s, and letting the side length of the square = s, we have;

Area of the square portion of the track = s × s = s² = 128 ft²

Therefore, s = √(128 ft²) = 8·√(2) ft.

Whereby the side length of the square is bounded by the diameter of the half circle, we have;

Length of the diameter of the half circle = s = 8·√(2) ft.

The length of the perimeter of the half circle = π·D/2 = π × 8·√(2)/2 = π × 4·√(2) ≈ 17.77 ft.

The perimeter of the track, which is the length of the track is made up of the three sides of the square opposite to the half circle and the circumference of the half circle.

Therefore;

The length of the track = 3 × 8·√(2) ft + π × 4·√(2) ft. = 4·√2×(π+6) ≈ 51.7 ft

The length of the track ≈ 51.7 ft

Which gives;

The track has three sides of the square and the distance round a half of a complete circle.

4 0
2 years ago
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