All categories

3 years ago

I need help with this please?

1 answer:

6 0

A. since they choose 4 people to form the committee and all the people chosen are teachers
from 5 teacher, we choose 4, 5C4
and
from 20 parents, we choose none, 20C0
5C4*20C0= 5

b. from 5 teacher choose 2, 5C2
and
from 20 parents choose 2, 20C2

5C2 * 20C2=1900

c.all parents
from 5 teachers choose 0, 5C0
and
from 20 parents choose 4, 20C4

5C0 * 20C4= 4845

d. from 5 teacher choose 1, 5C1
and
from 20 parents choose 3, 20C3

5C1 * 20C3= 5700

You might be interested in

Given: m || n, ∠1 ≅ ∠3<br> Prove: p || q

Leno4ka [110]

Answer:plz more info

Step-by-step explanation:do u have a pic of this question

5 0

3 years ago

Read 2 more answers

What is the binomial expansion of (x + 2y)7?

borishaifa [10]

<h2>Thus, the required "option 4)" is correct.</h2>

Step-by-step explanation:

We find,

$(x+2y)^7$

To find, the binomial expansion of of $(x+2y)^7$ = ?

We know that,

$(x+y)^{n} =^nC_0x^n+^nC_1x^{n-1}y+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+...+^nC_ny^n$

∴ $(x+2y)^7$

Here, n = 7, x = x and y = 2y

$(x+2y)^7$ = $^7C_0x^7+^7C_1x^{7-1}(2y)+^7C_2x^{7-2}(2y)^2+^7C_3x^{7-3}(2y)^3+^7C_4x^{7-4}(2y)^4+^7C_5x^{7-5}(2y)^5+^7C_6x(2y)^6+(2y)^7$ $=x^7+7x^{6(2y)+21x^{5}4y^2+35x^{4}8y^3+^35x^{3}16y^4+21x^{2}32y^5+7x64y^6+128y^7$

$=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7$

∴ The binomial expansion of of $(x+2y)^7$

$=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7$

Thus, the required "option 4)" is correct.

7 0

3 years ago

Karen received a $80 gift card for a coffee store. She used it in buying some coffee that cost $8.23 per pound. After buying the

aleksandrvk [35]

Answer:

Step-by-step explanation:

80 - 47.08 = 32.92

32.92/8.23 = 4

4 0

3 years ago

Read 2 more answers

The scale factor is <br> A 20:4<br> B 4:1<br> C 16:1<br> D 64:1

ser-zykov [4K]

B is the correct answer i think lol

8 0

3 years ago

A machine at Keats Corporation fills 64-ounce detergent jugs. The machine can be adjusted to pour, on average, any amount of det

horrorfan [7]

Answer:

The mean should be 64.63 ounces.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\sigma = 0.38$

The quality control inspector wants to adjust the machine such that at least 95% of the jugs have more than 64 ounces of detergent. What should the mean amount of detergent poured by this machine into these jugs be?

This is $\mu$ , for which X = 64 will have a pvalue of 1-0.95 = 0.05. So when X = 64, Z = -1.645.

$Z = \frac{X - \mu}{\sigma}$

$-1.645 = \frac{64 - \mu}{0.38}$

$64 - \mu = -1.645*0.38$

$\mu = 64 + 1.645*0.38$

$\mu = 64.63$

The mean should be 64.63 ounces.

6 0

3 years ago