54-10 ≥ 20+7x
44 ≥ 20 + 7x
44-20 ≥ 20-20 + 7x
24 ≥ 7x
24/7 ≥ 7x/7
3 3/7 ≥ x
Answer:
3) 5
4) 8.2
5) 6.8
6)FG = 6.4
7) EF = 3.6
8)DF = 4.8
Step-by-step explanation:
From the attached triangle, using trigonometric ratio we can find ∠G as; tan^(-1) (6/8)
Thus, ∠G = 36.87°
Still using trigonometric ratios;
FG/8 = cos 36.87°
FG = 8 cos 36.87°
FG = 6.4
3) EF + FG = EG
Since EG is 10, mean of EF and FG = 10/2 = 5
4) mean of EG and FG = (10 + 6.4)/2 = 8.2
5) EF + FG = EG
Thus; EF = EG - FG
EF = 10 - 6.4
EF = 3.6
Mean of EG and EF = (10 + 3.6)/2 = 6.8
6) FG = 6.4
7) EF = 3.6
8) Using trigonometric ratio;
DF/8 = sin 36.87
DF = 8 × 0.6
DF = 4.8
Step-by-step explanation:
perimeter of a semi- circle with a radius of 6cm
=2πr=2×π×6=12π cm
So you subtitute into the equation
so T=RH
if R=10 and H=35
so 10 per hour so
10 times 35 or (R times H)
so 350=T
b.
if is R=12 and H=40
subsitute and get
12 times 40 (RH) which is
480=T
Answer:
Step-by-step explanation:
Given the dimension of the homeowner's backyard to be width 18 yards long and length 16 yards long, the area of the rectangular backyard id expreesed as;
Area of rectangle = Length * Width
Area of the rectangular backyard = 18yards * 16yards
Area of the rectangular backyard = 288yards²
If they plan to put in a square pool with side length 5 yards long in the backyard, the area of the pool = 5yd*5yd = 25yd²
The remaining area that will contain the tiles = Area of the rectangular backyard - area of the pool
The remaining area that will contain the tiles = 288yd² - 25yd² = 263yd²
<em>Note that we cannot determine the amount of tiles they need to buy since we are not given the dimension of each tile to use</em>. The area needed for the tiles for the rest of the backyard is therefore 263yd².
Amount of tiles needed to buy can be expressed as 263/dimension of a tile.
