Answer:
900 yd²
Step-by-step explanation:
You can draw the pattern that would need to be folded to make the figure, then find the area of that pattern (or "net"). It consists of a rectangle 10 yards wide and 60 yards long, together with another that is 20 yards long and 15 yards wide. The total area is the sum of these ...
... area = (60 yd)(10 yd) + (20 yd)(15 yd)
... = 600 yd² +300 yd²
... = 900 yd²
Answer:
A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution
Step-by-step explanation:
Given that there is a continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers
Since the pdf is rectangular in shape and total probability is one we can say all values in the interval would be equally likely
Say if the interval is (a,b) P(X) = p the same for all places
Since total probability is 1,
we get integral of P(X)=p(b-a) =1
Or p= 
this is nothing but a uniform distribution continuous defined in the interval
A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution
Answer:
Step-by-step explanation:
There is a 1/12 probability that volume 1 will be correctly put in position 1.
If we assume that volume 1 is right, then since there are then only 11 books left to choose from, there is then a 1/11 prob that volume 2 will be in position 2. And so on. By the same reasoning there is 1/10 prob that volume 3 is then right, 1/9 prob for volume 4, 1/8 prob for volume 5, and 1/7 prob for volume 6,
and 1/6 prob for volume 7,and 1/5 prob for volume 8,and 1/4 prob for volume 9,and 1/3 prob for volume 10,and 1/2 prob for volume 11,and 1/1 prob for volume 12.
So the probability is 1 /(12*11*10*9*8*7*6*5*4*3*2*1) = 1 / 479,001,600 ....
<span>a · b = |a| |b| cos(theta)
=|a| * 14 * cos(45)
</span>a · b |a| =3
=>
|a| * 14 * cos(45) * |a| =3
|a| ² =3/(14cos(45))
|a| = sqrt(3/(14cos(45)))
=0.63868 (approx.)
Answer:
56 quizzes
Step-by-step explanation:
40 quizzes = 5 weeks
To find the unit rate of quizzes / week, we can divide both sides by 5
40/5 quizzes = 5/5 weeks
8 quizzes = 1 week
Multiply both sides by 7 to find the amount of quizzes in 7 weeks
8 * 7 quizzes = 1 * 7 weeks
56 quizzes = 7 weeks