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Hunter-Best [27]
2 years ago
7

Solve the Problems and Round Accordingly.

Mathematics
1 answer:
torisob [31]2 years ago
6 0

Answer:

1) 39.6474

2) 46.8741

3) 89.5382

4) 55.4417

5) 99.1744

6) 181.598

7) 8.076

8) 71.0826

11) 73.423

12) 78.573

13) 91.9519

14) 23.3715

15) 42.9531

16) 0.2386

17) 86.6819

18) 20.9584

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Hitman42 [59]

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4 0
2 years ago
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A biology experiment calls for 10 milliliters of water. How much water does the experiment call for in centiliters? (a.1 (b10 (c
Tasya [4]
It will call for A: One Centiliter. It's the same terms for stuff like millimeters and centimeters, 1 cm = 10 mm, 1 cl = 10 ml
7 0
3 years ago
Y=x-4 y=4x+2<br> whats the solution of system equations
Fittoniya [83]

Answer:

X=-2

Y=-6

Step-by-step explanation:

Since both equations are already expressed in the simplest form of y, then we equate them to be equal hence

x-4=4x+2

Bringing like terms together

-4-2=4x-x

Solving both sides

-6=3x

Making x the subject then

X=-6/3=-2

Subsrituting the value of x into any of the initial equations

Y=x-4 then y=-2-4=-6

Therefore, the solution is

X=-2

Y=-6

6 0
3 years ago
WILL GIVE BRAINEST
Naddika [18.5K]
The answer is A.....

7 0
3 years ago
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Please help it will help a lot i really need this!!
Lorico [155]

Answer:

A' = (0,0)

B'=(8,0)

C'=(8,2)

D'=(0,2)

It is not a rigid motion.

Step-by-step explanation:

To use the mapping rule, substitute the original x and y values in it.

The coordinates of A are (0,0).

Using the mapping rule, the x coordinate of A' = 2x0 = 0

Using the mapping rule, the y coordinate of A' = (1/2)x0=0

So A' will not change locations. The image will be at (0,0).

The coordinates of B are (4,0)

Using the mapping rule, the x-coordinate of B' = 2x4 = 8

Using the mapping rule, the y-coordinate of B' = (1/2)x0=0

Therefore the image of B' will be located at coorindate (8,0)

The coorindates of C are (4,4).

Using the mapping rule, the x-coordinate of C' = 2x4=8

Using the mapping rule, the y-coordinate of C' = (1/2)x4=2

Therefore the image of C' will be located at coordinate (8,2)

The coordinates of D are (0,4)

Using the mapping rule, the x-coordinate of D' = 2x0 = 0

Using the mapping rule, the y-coordinate of D' = (1/2)x4=2

Therefore the image of D' will be located at coordinate (0,2)

<em>Is the transformation a rigid motion?</em>

NO, this transformation is not a rigid motion because the relative distance between the points does not stay the same after they have been transformed. The transformation is not a translation , rotation, reflection, nor glide reflection.

6 0
2 years ago
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