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Gelneren [198K]
3 years ago
15

Consider a single spin of the spinner.

Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0

The question is incomplete

Find attached to the question, the appropriate diagram

Answer:

a) landing on an unshaded sector and landing on a number less than 2

b) landing on a shaded sector and landing on a 3

Step-by-step explanation:

Mutually exclusive events are two events that can occur separately on their own but they cannot occur together or at the same time.

The options given are explained below:

We have two shaded sectors: 1 and 4

We have two unshaded sectors : 2 and 3

a) landing on an unshaded sector and landing on a number less than 2

Looking at option a, we find out that it is possible for the spinners to land on an unshaded sector separately likewise on a number less than 2 but it cannot land on an unshaded sector AND and number less than 2 because looking at the spinner, the numbers on the unshaded sectors are 2 ( is equal to two) and 3 ( which is above 2).

Therefore this option is mutually exclusive and correct.

b) landing on a shaded sector and landing on a 3

It is possible to land on a shaded sector likewise it is possible to land on a 3 but it is not possible to land on a shaded sector and land on a 3 at the same time.

This is because, the number on the shaded sector is 1 and 4 and the number on the unshaded sector is 2 and 3, we have only one spinner so the spinner can only land on one sector at a time.

Therefore, Option b is a mutually exclusive event and it is a correct option.

c) landing on an unshaded portion and landing on an odd number

The unshaded portion on the spinner has number 2 and 3 on them, therefore it is possible to land on an unshaded portion and odd number which is 3 at the same time.

Option c is not a mutually inclusive event and it is wrong.

d) landing on a shaded sector and landing on an even number

The shaded sector on the spinner has number 1 and 4 on them, therefore it is possible to land on an shaded sector and even number which is 4 at the same time.

Option d is not a mutually inclusive event and it is wrong.

e)landing on a shaded sector and landing on a number greater than 3

The shaded sector on the spinner has number 1 and 4 on them, therefore it is possible to land on an shaded sector and a number greater than 3 which is 4 at the same time.

Option e is not a mutually inclusive event and it is wrong.

Therefore, option a and option b are mutually exclusive events and they are correct.

alexandr402 [8]3 years ago
4 0

Answer:

a.  landing on an unshaded sector and landing on a number less than 2

e  landing on a shaded sector and landing on a number greater than 3

Step-by-step explanation:

Two events ; for example events A and B are said to be mutually exclusive , if they cannot both occur simultaneously.In set theoretical notation , we say that the two sets A and B are disjoint set.

i.e

A ∩ B = ∅

Pr (A ∩ B) = 0

The intersection of A and B is an empty set and as such there is no intersection.

From the given options; option a and e are correct because ;

a.

landing on an unshaded sector and landing on a number less than 2

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection and as such these events are mutually exclusive.

e.

landing on a shaded sector and landing on a number greater than 3

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

The intersection of both events will be an empty set (∅)

As such these events are not mutually exclusive.

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