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3 years ago

Consider a single spin of the spinner.

Mathematics

2 answers:

steposvetlana [31]3 years ago

5 0

The question is incomplete

Find attached to the question, the appropriate diagram

Answer:

a) landing on an unshaded sector and landing on a number less than 2

b) landing on a shaded sector and landing on a 3

Step-by-step explanation:

Mutually exclusive events are two events that can occur separately on their own but they cannot occur together or at the same time.

The options given are explained below:

We have two shaded sectors: 1 and 4

We have two unshaded sectors : 2 and 3

a) landing on an unshaded sector and landing on a number less than 2

Looking at option a, we find out that it is possible for the spinners to land on an unshaded sector separately likewise on a number less than 2 but it cannot land on an unshaded sector AND and number less than 2 because looking at the spinner, the numbers on the unshaded sectors are 2 ( is equal to two) and 3 ( which is above 2).

Therefore this option is mutually exclusive and correct.

b) landing on a shaded sector and landing on a 3

It is possible to land on a shaded sector likewise it is possible to land on a 3 but it is not possible to land on a shaded sector and land on a 3 at the same time.

This is because, the number on the shaded sector is 1 and 4 and the number on the unshaded sector is 2 and 3, we have only one spinner so the spinner can only land on one sector at a time.

Therefore, Option b is a mutually exclusive event and it is a correct option.

c) landing on an unshaded portion and landing on an odd number

The unshaded portion on the spinner has number 2 and 3 on them, therefore it is possible to land on an unshaded portion and odd number which is 3 at the same time.

Option c is not a mutually inclusive event and it is wrong.

d) landing on a shaded sector and landing on an even number

The shaded sector on the spinner has number 1 and 4 on them, therefore it is possible to land on an shaded sector and even number which is 4 at the same time.

Option d is not a mutually inclusive event and it is wrong.

e)landing on a shaded sector and landing on a number greater than 3

The shaded sector on the spinner has number 1 and 4 on them, therefore it is possible to land on an shaded sector and a number greater than 3 which is 4 at the same time.

Option e is not a mutually inclusive event and it is wrong.

Therefore, option a and option b are mutually exclusive events and they are correct.

alexandr402 [8]3 years ago

4 0

Answer:

a. landing on an unshaded sector and landing on a number less than 2

e landing on a shaded sector and landing on a number greater than 3

Step-by-step explanation:

Two events ; for example events A and B are said to be mutually exclusive , if they cannot both occur simultaneously.In set theoretical notation , we say that the two sets A and B are disjoint set.

i.e

A ∩ B = ∅

Pr (A ∩ B) = 0

The intersection of A and B is an empty set and as such there is no intersection.

From the given options; option a and e are correct because ;

landing on an unshaded sector and landing on a number less than 2

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection and as such these events are mutually exclusive.

landing on a shaded sector and landing on a number greater than 3

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

The intersection of both events will be an empty set (∅)

As such these events are not mutually exclusive.

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What is the arc measure of \stackrel{\LARGE{\frown}}{AC}

algol [13]

Answer:

72°

Step-by-step explanation:

Given that the radius(r) of the circle is 10 units and the length of arc ABC is 16π

The length of arc ABC = $\frac{\theta}{360}*2\pi r$

Where θ is the central angle in degrees.

Since the length of arc ABC is 16π,

$16\pi=\frac{\theta}{360}*2\pi r\\16\pi=\frac{\theta}{360}*2\pi *10\\\theta=\frac{16\pi *360}{2 \pi *10} \\\theta=288^0$

The angle in a circle = 360°, therefore:

Central angle for arc AB (θ) = 360 - Central angle for arc ABC = 360 - 288 = 72°

Therefore the arc measure of arc AB is 72°

5 0

4 years ago

Coins are produced at the United States mint in Philadelphia. If the mint can make 45,000 coins each hour. How many coins can it

JulijaS [17]

They could make at least 1,080,000 coins during the 24hr period

6 0

3 years ago

A machine depreciates by 1/4 of its value each year. If it cost $50,000 new,

tester [92]

Step-by-step explanation:

The price of machine=$50000

depreciates rate (R )=1/4×100%

=25%

8 0

3 years ago

Pls help asap, I put attachments down below, I will also give brainliest

lesya [120]

Answer:

Question 1;

∴ The y values are 1.49 , 2.98 , 4.47 and 5.96

Question 2;

∴ The y values are 2.00 , 2.8 , 3.6 and 4.4

Question 3;

∴ The y values are -9 , -3 , 3 and 9

Question 4;

∴ y values are $\frac{1}{2}$ , $\frac{3}{4}$ , 1 and $\frac{5}{4}$

Step-by-step explanation:

Question 1;

Given data,

Apples cost $\$1.49$ per pound.

$x$ = weight in pound

$y$ = Cost in $\$$

Here the relation between $x$ and $y$ comes;

$y=x\times 1.49$ (equation 1)

Let, Plug all x value in equation 1;

when $x=1$ then $y=1\times 1.49=1.49$ ,

when $x=2$ then $y=2\times 1.49=2.98$ ,

when $x=3$ then $y=3\times 1.49=4.47$ ,

when $x=4$ then $y=4\times 1.49=5.96$ ,

∴ The y values are 1.49 , 2.98 , 4.47 and 5.96

Question 2;

From question,

Initial fees of cab is $\$$ 2.00 and Passengers are charged $\$$ 0.80 for every minute.

Let,

$x$ = Time in minutes

$y$ = Amount in $\$$

Here the relation between x and y comes;

$y=x\times 0.80 +2.00$ (equation 2)

Let,By plug all x value in equation 2;

When $x=0$ then $y=0\times 0.80+2.00=2.00$ ,

When $x=1$ then $y=1\times 0.80+2.00=2.8$ ,

When $x=2$ then $y=2\times 0.80+2.00=3.6$ ,

When $x=3$ then $y=3\times 0.80+2.00=4.4$ ,

∴ The y values are 2.00 , 2.8 , 3.6 and 4.4

Question 3;

Given relation between $x$ and $y$ ;

$y=6\times x +3$

Plug all the values of x in above equation,

When $x=-2$ then $y=(6\times -2) +3=-9$ ,

When $x=-1$ then $y=(6\times --1) +3=-3$ ,

When $x=0$ then $y=(6\times 0) +3=3$ ,

When $x=1$ then $y=(6\times 1) +3=9$ ,

∴ The y values are -9 , -3 , 3 and 9

Question 4;

Given relation between $x$ and $y$ ;

$y=(\frac{1}{4} \times x)+1$

Plug all the values of x in above equation,

When $x=-2$ then $y=(\frac{1}{4} \times -2)+1=\frac{1}{2}$ ,

When $x=-1$ then $y=(\frac{1}{4} \times -1)+1=\frac{3}{4}$ ,

When $x=0$ then $y=(\frac{1}{4} \times 0)+1=1$ ,

When $x=1$ then $y=(\frac{1}{4} \times 1)+1=\frac{5}{4}$ ,

∴ y values are $\frac{1}{2}$ , $\frac{3}{4}$ , 1 and $\frac{5}{4}$

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4 years ago

AthXL for School:

Arlecino [84]

Answer:

$28.5

Step-by-step explanation:

14-6.5=7.5

7.5x$3.8=28.5

8 0

3 years ago