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Leno4ka [110]
3 years ago
6

The right arrow symbol used to show the transition from a point to its image after a transformation is not contained within the

Equation Editor. If such a symbol is needed, type "RightArrow." For example: P(0, 0) RightArrow P′(1, 2).
Triangle ABC has coordinates
A (1,4);B(3,−2); and C(4,2).
Find the coordinates of the image
A'B'C' after a reflection over the x-axis.
Mathematics
1 answer:
Bumek [7]3 years ago
7 0

Given:

Vertices of triangle ABC are A (1,4), B(3,−2) and C(4,2).

Triangle ABC reflected over the x-axis to get the triangle A'B'C'.

To find:

The coordinates of the image A'B'C'.

Solution:

If a figure reflected over the x-axis, then rule of transformation is

(x,y)\to (x,-y)

Now, using this rule, we get

A(1,4)\to A'(1,-4)

B(3,-2)\to B'(3,2)

C(4,2)\to C'(4,-2)

Therefore, the coordinates of the image  A'B'C' after a reflection over the x-axis are A'(1,-4), B'(3,2) and C'(4,-2).

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The answer is A

Step-by-step explanation:

Starting from -3 in the Y values of option A. If you subtract three from each value, you will get the next value to the right.

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alukav5142 [94]

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2 years ago
What is 1/2÷3 as a fraction?
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A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 9% vinegar, and the second brand co
pishuonlain [190]
Let the amount of the first brand be x, and let the amount of the second brand be y.
0.09x + 0.14y = 240 * 0.13 .................(1)
x + y = 240 ..............(2)
y = 240 - x .......................(3)
Plugging the value for y from equation (3) into equation (1), we get:
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