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zalisa [80]
3 years ago
5

there are 7 teams in the soccer tournament.there are two coaches on each team and 10 kids play on each team.which sentence below

represents how many people in total are participating in the tournament? A. 14 coaches+70 kids b.70 coaches + 20 kids c.14 coaches +20 kids d.20 coaches +14 kids
Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

I think it's letter B, sorry I'm not sure

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Answer:

251.3274cm

Step-by-step explanation:

L / 240 = C / 2π

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Identify this prism and describe it using the following vocabulary terms: base, edge, face, and vertex.
devlian [24]

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the person above me is correct

Step-by-step explanation:

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PLEASE ANSWER ILL MAKE YOU BRAINLIEST 2 questions
GREYUIT [131]

Answer:

Wait what is the question the question you put in was

"PLEASE ANSWER ILL MAKE YOU BRAINLIEST 2 questions"

Step-by-step explanation:

4 0
3 years ago
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Jenna drew irregular quadrilateral ABCD inscribed in circle P. She knows that: m∠3=2⋅m∠1, and m∠2=2⋅m∠4, and m∠2+m∠3=360°. What
Mrrafil [7]

Answer:

The generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°

Step-by-step explanation:

We are given the following from what she knows

m∠3=2⋅m∠1... 1

m∠2=2⋅m∠4 ... 2

m∠2+m∠3=360 ... 3

From what is given, we can substitute equation 1 and 2 into equation 3 as shown:

From 3:

m∠2+m∠3=360

Substituting 1 and 2 we will have:

2⋅m∠4 + 2⋅m∠1 = 360

Factor out 2 from the left hand side of the equation

2(m∠4+m∠1) = 360

Divide both sides by 2

2(m∠4+m∠1)/2 = 360/2

m∠4+m∠1 = 180°

Since the sum of two supplementary angles is 180°, hence the generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°

7 0
3 years ago
Find the number of ways of arranging the numbers
Doss [256]

First of all, note that all integers are either 0,1, or 2 modulo 3 (if you're not familiar with this terminology, it means that every integer is either a multiple of 3, or it is 1 or 2 away from a multiple of 3).

So, we can think of our numbers as

\begin{array}{c|c}x&x\mod 3\\0&0\\1&1\\2&2\\3&0\\4&1\\5&2\\6&0\\7&1\\8&2\\9&0\end{array}

In order to make sure that the sum of any three adjacent numbers is divisible by 3, we have to make sure that any group of 3 three adjacent numbers contains a 0, a 1 and a 2. This is possible only if we arrange our 9 numbers in 3 groups of 3 numbers containing 0,1 and 2 exactly once, repeating always the same pattern.

For example, we could arrange our numbers following the pattern

0,1,2,0,1,2,0,1,2

or

2,0,1,2,0,1,2,0,1

We have 3!=6 possible patterns. Suppose for example that we choose the pattern

0,1,2,0,1,2,0,1,2

One possible way of following this pattern would be the arrangement

3,1,2,6,4,5,9,7,8

In fact, we substituted every '0' with a multiple of 3 (3, 6 or 9), every '1' with a number 1 away from a multiple of 3 (1, 4 or 7) and every '2' with a number 2 away from a multiple of 3 (2, 5 or 8).

This means that, once we fix a patter, we have 3 choices for the first 3 slots, 2 choices for the next 3 slots, and the final slot will be fixed. So, we have

3\cdot 3\cdot 3\cdot 2 \cdot 2 \cdot 2 = 216

possible ways of following a fixed pattern. Since the number of patterns was 6, we have

216\cdot 6 = 1296

possible arrangements.

7 0
3 years ago
Read 2 more answers
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