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Alekssandra [29.7K]
2 years ago
5

Find the value of x and y in the parallelogram below.

Mathematics
2 answers:
Slav-nsk [51]2 years ago
8 0

Solution:

<u>It should be noted:</u>

  • A rhombus's opposite sides are always equal.

<u>Thus:</u>

  • 3y + 1 = 94
  • -x + 2 = 72

Simplify both equations to find x and y.

<u>Finding x:</u>

  • -x + 2 = 72
  • => -x = 72 - 2
  • => -x = 70
  • => x = -70

<u>Finding y:</u>

  • 3y + 1 = 94
  • => 3y = 94 - 1
  • => 3y = 93
  • => y = 31
yuradex [85]2 years ago
8 0

Opposite sides are equal

\\ \rm\hookrightarrow -x+2=72

\\ \rm\hookrightarrow -x=-70

\\ \rm\hookrightarrow x=70

And

\\ \rm\hookrightarrow 3y+1=94

\\ \rm\hookrightarrow 3y=93

\\ \rm\hookrightarrow y=31

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1600 dollars is placed in an account with an annual interest rate of 5.25%. How much will be in the account after 25 years, to t
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Step-by-step explanation:

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y=ab^x

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3 0
3 years ago
What is an<br> equation of the line that passes through the points (-3,-7) and (8,-7)?
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graph attached.

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4 0
3 years ago
Find an equation of the line is the perpendicular to 30X-5Y=5 and passes through the point (0,-3).
timurjin [86]

Answer:

y = (\frac{-1}{6})x - 3

Step-by-step explanation:

Given line = 30x - 5y = 5 or y = 6x + 1

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m = slope of the line

c = constant

As we know, if two lines are perpendicular to each other, the value of product of there slopes are -1.

so, slope of given line × slope of perpendicular line = -1

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⇒ m = \frac{-1}{6}

By substitutiong the value of m in the equation, we get;

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as the point (0,-3) passes through the line, we get;

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The line which is perpendicular to the given line and passes through (0,-3) is  y = (\frac{-1}{6})x - 3 .

5 0
3 years ago
Read 2 more answers
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