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a_sh-v [17]
2 years ago
5

What unit of measurement would you use to measure the length of your foot?

Mathematics
1 answer:
UNO [17]2 years ago
6 0

Answer:

centimeter

Step-by-step explanation:

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I think it would be 11 because if it was 12 hours it would been way more then $1265. they are asking you for hours not minutes. I am pretty sure it would be 11. I hope this helped!
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3 years ago
Select the comparison that is correct. (2 are right) A eighty-one tenths > 8.27 B Six and seventy-nine thousandths 50.453 D 3
madreJ [45]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Graph the line that passes through the given point and has the given slope m!
Veseljchak [2.6K]

Answer:

The line would be y = -1/4x + 27/4

Step-by-step explanation:

In order to find this, we first need to note that the original slope is -1/4. And since parallel lines have the same slope, we know our new line will have that same slope. Now, we can use that slope and the point in point-slope form and solve for y.

y - y1 = m(x - x1)

y - 6 = -1/4(x - 3)

y - 6 = -1/4x + 3/4

y = -1/4x + 27/4

7 0
3 years ago
What is the volume of the composite figure? 1,200 units3 4,400 units3 5,040 units3 6,000 units3
swat32

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6000

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
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