Answer:
C
Step-by-step explanation:
The answer is C.
Answer:
We have:
x < 4 AND x > a.
if a = 4 and we use an "or" instead of the "and" we have:
x < 4 or x > 4.
This is:
"x is larger than 4 or smaller than 4."
Then the solution of this is all the real numbers except the value x = 4.
The set of solutions can be written as:
{xI x ∈ R \ [4]}
Where this reads:
"x belongs to the set of the reals minus the number 4".
Or we also could write it as:
x ∈ (-∞, 4) ∪ (4, ∞)
Where we have two open ends in the "4" side, so the value x = 4 does not belong to that set.
Answer:
x=1
Explain:
y=2x^2−4x+1
dy/dx=4x-4
The line of symmetry will be where the curve turns (due to the nature of the
x^2 graph.
This is also when the gradient of the curve is 0.
Therefore, let
dy/dx=0
This forms an equation such that:
4x−4=0
solve for x,
x=1
and line of symmetry falls on the line
x=1
