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3 years ago

1/2 divided by 2/3 simplest form

Mathematics

2 answers:

Kazeer [188]3 years ago

7 0

Answer:

$\frac{3}{4}$

Step-by-step explanation:

$\frac{1}{2} \div \frac{2}{3}$

$\frac{1}{2} * \frac{3}{2}$

$\frac{3}{4}$

Hope this helps!

Semmy [17]3 years ago

7 0

Answer:

3/4

Step-by-step explanation:

$\frac{1}{2}*\frac{3}{2}=\frac{\frac{1}{2}}{\frac{2}{3}}$

$\frac{1}{2}*\frac{3}{2}=\frac{3}{4}$

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Murljashka [212]

Answer:

Step-by-step explanation:

an equation is : Use the point-slope formula.

y - y_1 = m(x - x_1) ; m : the slope when : x_1 = -3 and y_1 = 7

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so : m= 1/2

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3 years ago

The decimal d is formed by writing in succession all the positive integers in increasing order after the decimal point; that is,

Maksim231197 [3]

Answer:

Step-by-step explanation:

We are given that a decimal number d

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Where d is formed by writing in succession all the positive integers in increasing order after decimal point.

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4 years ago

In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct

kari74 [83]

Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

$P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279$

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

$=(0.93\times0.03)+(0.10\times0.97)\\=0.1249$

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

$P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234$

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

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3 years ago