Answer:
0.785398163 rad
Step-by-step explanation:
The given triangle is a right-angled triangle. This means that special trig identities can be applies
<u>These identities are as follows:</u>
sin (theta) = opposite / hypotenuse
cos (theta) = adjacent / hypotenuse
tan (theta) = opposite / adjacent
<u>Now, for the unknown theta in the triangle:</u>
The opposite side is 16 and the hypotenuse is 20
This means that we will use the <u>sin</u> not the cos as Bob did
<u>The solution will be as follows:</u>
sin (theta) = opposite / hypotenuse
sin (theta) = 16 / 20
theta = sin^-1(16/20)
theta = 53.13°
Hope this helps :)
Answer:
<em>The graph of </em>y + 1 = −3/5 (x − 4)<em> would be a straight line. The graph figure is attached below.</em>
Step-by-step explanation:
As the linear equation y + 1 = −3/5 (x − 4) is given.
Since y-y₁ = m (x - x₁) is the Point-slope form is the general form y-y₁=m(x-x₁) for linear equations.
Hence, from the linear equation we can determine the slop which is m = -3/5
Also, when we put x = 0 in the linear equation, we determine the y-intercept as follows:
y + 1 = −3/5 (x − 4)
y + 1 = -3/5(-4) ∵x = 0
y = 12/5 - 1
y = 7/5
y-intercept: 7/5
Hence,
Table for some points can be made for x and values as:
<h3><em>x y</em></h3>
0<em> </em><em> 7/5</em>
<em>1 4/5</em>
<em />
<em>The graph of </em>y + 1 = −3/5 (x − 4)<em> would be a straight line. The graph figure is attached below.</em>
<em />
<em>Keywords: graph, straight line</em>
<em>Learn more about graph of a straight line from brainly.com/question/11488685</em>
<em>
#learnwithBrainly</em>
Answer:
y = 1(x + 3)² - 6
Step-by-step explanation:
The <em>standard form</em> of a quadratic function is
y = ax² + bx + c
The <em>vertex form</em> of a parabola is
y = a(x - h)² + k
where (h, k) is the <em>vertex</em> of the parabola.
h = -b/(2a) and k = f(h)
In the equation y= x² + 6x + 3
a = 1; b = 6; c = 3
=====
<em>Calculate h
</em>
h = -6/(2×1)
h = -6/2
h = -3
=====
<em>Calculate k
</em>
k = 1(-3)² + 6(-3) + 3
k = 9 - 18 +3
k = -6
=====
Write the <em>vertex form of the equation</em>
y = 1(x + 3)² - 6
The graph is a parabola with a vertex at (-3, -6).