We have a formula for that( according to the Intersecting chords theorem)

3×4=2×jk
6=jk
From left to right it’s 1, 49, 9, 70
Answer:
36
Step-by-step explanation:
someone told me. this will make it easier for u
F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)
g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)
f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)
Answer: Third Option (2x+3)/(x+2)
Answer:
(3.5,3)
Step-by-step explanation:
Midpoint= (x¹+x²/2, y¹+y²/2)
x¹=4
x²=3
y¹=0
y²=6
Put your values into the formula
(4+3/2,0+6/2)
(7/2, 6/2)
(3.5,3)